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Luda [366]
3 years ago
7

C15H28 is the formula of

Chemistry
1 answer:
Olegator [25]3 years ago
5 0
Cyclopentadecene is it
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What volume of oxygen gas is needed to completely combust 0.202L of butane (C4H10) gas?
saveliy_v [14]

Answer:

look at the file :)

Explanation:

4 0
3 years ago
Help please I really really need it now ​
postnew [5]
1. A 2. B 5. B this is all I know hope it helps
5 0
2 years ago
Will bromine react with sodium and why?
Archy [21]

<span><span>When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br: </span></span>

<span><span />So here we the know the valence electrons for each;</span>

<span><span>Na:  (2e)
Br:  (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>

<span><span /></span><span><span>

</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>

<span>
</span>

4 0
3 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
From the given elements Na, P , Ca ,Br which one has highest first ionization energy , ,smallest atomic size , most metallic cha
madam [21]

Answer:

highest first ionization energy - Br

smallest atomic size - Br

most metallic character - Na

Explanation:

Ionization energy of Br is higher than P because higher zeff value

Sodium is more metallic than calcium because it is able to loose electron more readily as compared to calcium because of higher electro positivity.

Atomic radius of Br is the smallest as its atomic radius is 114, P (115), Ca (197), Na (186)

 

 

5 0
3 years ago
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