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ivann1987 [24]
2 years ago
8

Which of the following sets of elements could replace the generic "X" symbol with their own to produce a valid dot notation for

the element(s)?
Select one:

a.
carbon, silicon, and germanium


b.
oxygen, sulfur, and selenium


c.
boron, aluminum, and gallium


d.
nitrogen, phosphorus and arseni

Chemistry
2 answers:
Vsevolod [243]2 years ago
5 0

Answer:

a

Explanation:

Because of their valence electron

Carbon, Silicon and germanium has 4 as their valence electron

BartSMP [9]2 years ago
5 0

Nitrogen, phosphorus, and arsenic can replace the generic "X" symbol as they have five valence electrons in their outer shell.

<h3>What is a dot notation?</h3>
  • A Lewis electron-dot symbol or dot notation is a way of representing the valence electrons of an atom using dots around the symbol of the element.
  • The dots are equivalent to the valence electrons in an atom
  • These dots are arranged on the left and right and above and below the symbol
  • No more than two dots are arranged on a side
<h3>What are the valence electrons?</h3>
  • Valence electrons are the electrons that are positioned in the outermost shell of an atom
  • They are the farthest from the nucleus and hence least tightly held electrons by the nucleus
  • Valence electrons of an atom participate in the bond and reaction and hence, they determine the reactivity of an element.

Thus, nitrogen, phosphorus, and arsenic replace the X symbol as they 5 valence electrons in their outermost shell and produce a valid dot notation.

Learn more about valence electrons:

brainly.com/question/371590

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Which of the following sets of elements could replace the generic "X" symbol with their own to produce a valid dot notation for the element(s)?

Select one:

a. carbon, silicon, and germanium

b. oxygen, sulfur, and selenium

c. boron, aluminum, and gallium

d. nitrogen, phosphorus, and arsenic

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r
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n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
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S
O
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40
x
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2
200
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142
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x
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2
200
⋅
142
=
2
⋅
40
x
x
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142
2
⋅
40
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100
⋅
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40
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m
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