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2 years ago

Suppose you have a sample of table salt (NaCl) that has a mass of 100.0 grams. If

Chemistry

1 answer:

IgorC [24]2 years ago

5 0

Taking into account the definition of molarity, the concentration of the solution is 0.855 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of NaCl</h3>

In this case, you have:

number of moles of NaCl= $100 grams\frac{1 mole}{58.45 grams} =$ 1.71 moles (being 58.45 g/mole the molar mass of NaCl)
volume 2 L

Replacing in the definition of molarity:

$Molarity=\frac{1.71 moles}{2 L}$

Solving:

Molarity= 0.855 $\frac{moles}{liter}$

Finally, the concentration of the solution is 0.855 $\frac{moles}{liter}$ .

Learn more about molarity:

<u>brainly.com/question/9324116</u>

<u>brainly.com/question/10608366</u>

<u>brainly.com/question/7429224</u>

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calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is $-22Jmole^-^1k^-^1$

(b) The normal boiling point of water (J·K−1·mol−1) is $-109Jmole^-^1K^-^1$

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole

Explanation:

Lets calculate

(a) - General equation -

$(\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p$ = $-5_m(\beta )+5_m(\alpha )$ = $-\frac{\Delta H}{T}$

$\alpha ,\beta$ → phases

ΔH → enthalpy of transition

T → temperature transition

$(\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p$ = $= -\frac{\Delta_fH}{T_f}$

= $\frac{-6.008kJ/mole}{273.15K}$ ( $\Delta_fH$ is the enthalpy of fusion of water)

= $-22Jmole^-^1k^-^1$

(b) $(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}$

= $\frac{40.656kJ/mole}{373.15K}$ ( $\Delta_v_a_p_o_u_rH$ is the enthalpy of vaporization)

= $-109Jmole^-^1K^-^1$

$[\mu(l-5$ ° $C)-\mu(l,0$ ° $C)]$ = $[\mu(s-5$ ° $C)-\mu(s,0$ ° $C)]$ $=-S_m$ ΔT

$\mu(l,-5$ ° $C)-\mu(s,-5$ ° $C)=-Sm\DeltaT [\mu(l,0$

$\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)$

= 109J/mole

6 0

3 years ago

Which metal can be extracted from bauxite ore?

Finger [1]

Aluminum
Bauxite ore is the world's primary source of aluminum. The ore must first be chemically processed to produce alumina (aluminum oxide). Alumina is then smelted using an electrolysis process to produce pure aluminum metal. Bauxite is typically found in topsoil located in various tropical and subtropical regions.

8 0

3 years ago

Read 2 more answers

Is this a model of an element, a compound, or a mixture? Explain your reasoning.

grandymaker [24]

Answer:

A mixture

Explanation:

Yes

6 0

4 years ago

What mass of AI2O3 forms, knowing the molar mass of Al2O3 is 102 g/mol ?

TiliK225 [7]

Question

What mass of Al₂O₃ form is produced if 25.00 g of aluminum (al) is reacted completely?, knowing the molar mass of Al₂O₃ is 102 g/mol?

Atomic mass of Al =27 and O = 16

The molar mass of Al₂O₃ = 102.

Mass of aluminium in 102 g of Al₂O₃ = 54 g

54 g Al => 102 g Al₂O₃

25g Al => x g Al₂O₃

x = 25*102/54 = 47.2 g Al₂O₃

To solve more questions on molar mass check here:

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1 year ago

Describe the region in model 1 where the highest concentration of hydrogen ion (h+) is located.

Jobisdone [24]

The highest concentration of hydrogen ion (H+) is located in the intermembrane space. The intermembrane space is the space between inner membrane and the outer membrane of the mitochondrion or chloroplast. THe main function of intermembrane is oxidative phosphorylation.

8 0

3 years ago