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Dmitry_Shevchenko [17]
3 years ago
11

Can someone help me with the question in the image. if it is correct i will mark as brainliest

Chemistry
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

If I'm right, I beleive it is the last question-

I really hope this helps ^-^

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Calculate the standard entropy of vaporization of ethanol at its boiling point 285 K. The standard molar enthalpy of vaporizatio
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Answer:

standard entropy of vaporization of ethanol = 142.105 J/K-mol

Explanation:

given data

enthalpy of vaporization of ethanol = 40.5 kJ/mol = 40.5 × 10^{3} J/mol

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to find out

standard entropy of vaporization of ethanol

solution

we get here standard entropy of vaporization of ethanol that is expess as

standard entropy of vaporization of ethanol ΔS = \frac{\Delta H}{T} .............1

here ΔH is enthalpy of vaporization of ethanol and  T is temperature

put value in equation 1

standard entropy of vaporization of ethanol ΔS =  \frac{40.5*10^3}{285}

standard entropy of vaporization of ethanol = 142.105 J/K-mol

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