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3 years ago

Answer these questions:

Physics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

1) Seven tectonic plates can be identified in the earth today.

2) The old sea floor sinks back into the earth to be recycled at the subduction zone.

3) The world's last supercontinent is known as Pangaea.

4) Pangaea began breaking up approximately 175 million years ago.

Explanation:

I hope this helped!!!!

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The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25

tino4ka555 [31]

Answer:

Mercury:

.85

pea

Venus:

2.1

gumball

Earth:

2.2

gumball

Mars:

1.2

marble

Uranus:

grapefruit

Neptune:

8.6

softball

Explanation:

I have no clue if I'm right but hopefully, I am

3 0

3 years ago

Gravity causes all falling objects to accelerate at a rate of 98 m/s2.<br> O True<br> O False

aleksandrvk [35]

It’s true the acceleration of falling objects on earth due to gravity is 98ms2

8 0

3 years ago

What is the value of work done on an object when a 50-newton force moves it 15 meters in the same direction as the force?

Volgvan

Answer:

W = 750 Joules.

Explanation:

Given that,

Force acting on the object, F = 50 N

Distance moved by the object, d = 15 m

To find,

Work done by the object

Solution,

Let W is the work done by the object. It is given by the product of force and distance. Its expression is given by :

$W=F\times d\ cos\theta$

Here, $\theta=0$ (force and distance are in same direction)

$W=F\times d$

$W=50\ N\times 15\ m$

W = 750 Joules

So, the work done by the force is 750 Joules.

4 0

3 years ago

A cannon tilted upward at 30° fires a cannonball with a speed of 100 m/s. At that instant, what is the component of the cannonba

Sonja [21]

Answer:

the cannonball’s velocity parallel to the ground is 86.6m/S

Explanation:

Hello! To solve this problem remember that in a parabolic movement the horizontal component X of the velocity of the cannonball is constant while the vertical one varies with constant acceleration.

For this case we must draw the velocity triangle and find the component in X(see atached image).

V= Initial velocity=100M/S

$cos30=\frac{Vx}{V}$

V= Initial velocity=100M/S

Vx=cannonball’s velocity parallel to the ground

Solving for Vx

Vx=Vcos30

Vx=(100m/S)(cos30)=86.6m/s

the cannonball’s velocity parallel to the ground is 86.6m/S

6 0

3 years ago

Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength

Vikentia [17]

Answer:

$\frac{E_{A}}{E_{B}}=4$

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

$E=\frac{F}{q}$ .

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

$F=\frac{kQq}{r^{2}}$ .

By substitution we get that

$E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}$

Now, letting $E_{A}$ be the electric field at point A, letting $E_{B}$ be the electric field at point B, and letting R be the distance from the charge to A:

$E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}$ .

The ration of the electric fields is

$\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4$

This means that at half the distance, the electric field is four times stronger.

4 0

3 years ago