(2k² + 5k - 6)(3k - 1)
(6k³ - 2k² + 15k² - 5k - 18k + 6)
6k² + 13k² - 23k + 6
Use the FOIL method to simplify the problem.
(FOIL stands for first outer, inner, last)
Answer:
a+b = 12
Step-by-step explanation:
There are 36 possible outcomes for rolling two dice. Let A be the number rolled by Abed and D be the number rolled by Dawn. The sample space, in the format [A,D], of all of the possibilities in which Dawn's number is larger is:
[5,6]
[4,5] [4,6]
[3.4] [3,5] [3.6]
[2,3] [2.4] [2,5] [2.6]
[1,2] [1,3] [1.4] [1,5] [1.6]
There are 15 ways out of 36 possible ways of Dawn getting the higher number. In the simplest form:

-10d^2 + 11d - 2
To find this, distribute the - to 7d^2 - d - 6.
This will give you a new equation of:
-3d^2 + 10d - 8 -7d^2 + d + 6
Combine like terms to get the answer above.
Hope this helps!
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h
1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3)
whole area=A1+A2=25/2+75/2=100/2=
50