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Olin [163]
3 years ago
12

You are given a solution of sugar and sand and water your task is to separate sugar from sand which of the following experimenta

l designs would you choose
Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

Explanation:

Filtration followed by evaporation:

To separate the mixture of sand and sugar, it is best to use the separation technique of filtration then evaporation.

Pour the water into the mixture. The sugar will dissolve with time in the water. Sand is made up of quartz and does not dissolve in water.

After the dissolution, filter the solution to separate the sand using a filter paper.

Dry the sand thereafter then proceed to evaporate the sugar with water solution. Evaporation will turn water into vapor and the sugar crystals will be left behind.

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viva [34]
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</span>CH, CH4, C4H10, C8H18, C16H34

Hope this answers the question. Have a nice day.
8 0
3 years ago
PLS HELP The average atomic mass of carbon is 12.01 amu. Based on the atomic
Masteriza [31]

Answer:

B. There is a very large percentage of C-12.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

In such a way, the answer will be B. There is a very large percentage of C-12.

Regards!

7 0
3 years ago
Is a mirror transparent, translucent, or opaque? ​
kozerog [31]
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6 0
3 years ago
Read 2 more answers
An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


3 0
3 years ago
230 in scientific notation
rewona [7]
230 in scientific notation is:

2.3 x 10^2
7 0
4 years ago
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