I would go with C because that seems like the best answer choice
Answer:
here
Explanation:
Ka=Cx^2/1-x
Ka =1.8 x 10^-5
C = 0.1
If we consider x is negligible ie., x~0
Then x=(Ka/c)^0.5
={1.8 x 10^-5/0.1)^0.5 =0.01342
So concetration of H+ ion =Cx
=0.1 x 0.01342 =0.001342
pH=- log(0.001342) =2.87
However it is only an approximate method. Without using approximation, if we solve equation
Ka =Cx^2/1-x , for value of 'x', where C=0.1 then
We get x = 0.01273
So concetration of H+ ion = Cx
=0.1 x 0.01273 =0.001273
pH = - log (0.001273)
= 2.89.
There would be no net movement of glucose
The given statement is wrong. Glucose solutions are not electrolytes and therefore do not conduct electricity.
Is sodium chloride a good conductor of electricity? Simply by dissolving or dissolving it in water, it cannot conduct electricity as a solid.
Saline contains Na+ and Cl- ions. If ions are present in the solution, these ions can move through the solution and carry an electric current. Pure water and sugar solutions do not contain significant ions. Sugar molecules do not break down into ions when dissolved.
When glucose is added to water, it dissolves readily but does not dissociate into ions. Therefore, a glucose solution is not an electrolyte and is not a conductor of electricity.
Substances that dissolve in water to form a conductive solution are called electrolytes. Substances that dissolve in non-conductive solutions are called non-electrolytes. All soluble ionic compounds are electrolytes.
Learn more about glucose here;
brainly.com/question/461228
#SPJ4
