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trasher [3.6K]
3 years ago
12

What volume does 4.53 moles of hydrogen at 1.78 atm and 301 K occupy

Chemistry
2 answers:
AleksAgata [21]3 years ago
5 0
V = nRT / P = (4.53 mol) x (0.08205746 L atm/K mol) x (301 K) / (1.78 atm) = 62.9 L
Darina [25.2K]3 years ago
3 0

Explanation:

According to ideal gas equation, product of pressure and volume equals n times R times T.

Mathematically,            PV = nRT

where         P = pressure

                   V = volume

                   n = number of moles

                   R = gas constant

                   T = temperature

Since, it is given that no. of moles is 4.53 mol, pressure is 1.78 atm and temperature is 301 K. Value of R will be 0.082 L atm K^{-1}mol^{-1} Therefore, calculate the volume as follows.

                                 PV = nRT

         1.78 atm \times V = 4.53 mol \times 0.082 L atm K^{-1} mol^{-1} \times 301 K

                              V = \frac{111.81 L atm}{1.78 atm}

                                  = 62.81 L

Thus, we can conclude that volume of hydrogen will be 62.81 L.

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If scientists had tried to repeat thomosons experiment and found that they could not would thomosons cocnclusion still have been
lesantik [10]

Answer:

No

Explanation:

The conclusions from Thomoson's claims would be invalid if his experiment could not be replicated.

<em>One of the attributes of a valid experiment in science is replication. That is, an experiment must be repeatable with similar outcomes under similar conditions as the original experiment when independently performed by another scientist. Once an experiment cannot be replicated, the outcomes of such an experiment become invalid in science.</em>

Hence, <u>Thomoson's conclusion would be invalid if his experiment could not be replicated. </u>

5 0
3 years ago
A gaseous mixture of O2 and N2 contains 37.8% nitrogen by mass. What is the partial pressure of oxygen in the mixture if the tot
kondor19780726 [428]

Answer: The partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

Explanation:

mass of nitrogen = 37.8 g

mass of oxygen = (100-37.8) g = 62.2 g

Using the equation given by Raoult's law, we get:

p_A=\chi_A\times P_T

p_{O_2} = partial pressure of O_2 = ?

\chi_{O_2} = mole fraction of O_2=\frac{\text{Moles of }O_2}{\text{Total moles}}

P_{T} = total pressure of mixture  = 525 mmHg

{\text{Moles of }O_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{62.2g}{32g/mol}=1.94moles

{\text{Moles of }N_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{37.8g}{28g/mol}=1.35moles

Total moles = 1.94 + 1.35 = 3.29 moles

\chi_{O_2}=\frac{1.94}{3.29}=0.59

p_{O_2}=\chi_{O_2}\times P_T=0.59\times 525=310mmHg

Thus the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

7 0
3 years ago
How many liters of CO2 are formed when 14.0 g of CaCO3 react at 1.00 atm and 1000K
Gnesinka [82]

Answer: 11.5

Explanation:

7 0
3 years ago
Read 2 more answers
I don't know how to do this can I get the answers plz it's due in 1 hour
katrin [286]
Okay, so even if I just gave you the answers, your teacher needs work on it too so it'll be easier/better if I just explain how to do it.
Basically, both sides need to have the same number of molecules. To do this, we make charts. This is the first side of number one:
Na - 1
Mg- 1
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The subscript gives F two molecules, and the other ones only each have one. This is the second side:
Na- 1
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So they're not equal. To fix this, we add coefficients. These are numbers that are going to appear in the front of each compound/element and changes the number of molecules of the WHOLE compound/element. We need two F on the second side, so we'll put a coefficient of 2 in front of NaF. The new chart for the second side is this:
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Now we've fixed the F, but now Na is off! So let's go to the first side again and see what we can do. We can put a 2 in front of the Na. The new chart is this:
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Now both sides are the same. The full new equation is:
2Na + MgF(sub2) = 2NaF + Mg
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4 0
3 years ago
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How the proton H gradient is used to make ATP
sladkih [1.3K]

Answer:

The proton gradient produced by proton pumping during the electron transport chain is used to synthesize ATP. Protons flow down their concentration gradient into the matrix through the membrane protein ATP synthase, causing it to spin (like a water wheel) and catalyze conversion of ADP to ATP.

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