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trasher [3.6K]
3 years ago
12

What volume does 4.53 moles of hydrogen at 1.78 atm and 301 K occupy

Chemistry
2 answers:
AleksAgata [21]3 years ago
5 0
V = nRT / P = (4.53 mol) x (0.08205746 L atm/K mol) x (301 K) / (1.78 atm) = 62.9 L
Darina [25.2K]3 years ago
3 0

Explanation:

According to ideal gas equation, product of pressure and volume equals n times R times T.

Mathematically,            PV = nRT

where         P = pressure

                   V = volume

                   n = number of moles

                   R = gas constant

                   T = temperature

Since, it is given that no. of moles is 4.53 mol, pressure is 1.78 atm and temperature is 301 K. Value of R will be 0.082 L atm K^{-1}mol^{-1} Therefore, calculate the volume as follows.

                                 PV = nRT

         1.78 atm \times V = 4.53 mol \times 0.082 L atm K^{-1} mol^{-1} \times 301 K

                              V = \frac{111.81 L atm}{1.78 atm}

                                  = 62.81 L

Thus, we can conclude that volume of hydrogen will be 62.81 L.

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2 years ago
density of a piece of ebony wood is 1.174 g/ml. what is the volume in quarts of a 2.1549 lb piece of this ebony wood?
lapo4ka [179]

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Explanation:

Given parameters:

Density of ebony wood = 1.174g/ml

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Unknown:

Volume of the wood in quarts = ?

Solution:

Density is defined as the mass per unit volume of a substance.

Mass is the quantity of matter the wood contains.

Volume is the space it occupies.

To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.

Then convert the volume from mL to quarts.

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Volume = \frac{977.5}{1.174} = 832.6mL

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Density brainly.com/question/8441651

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7 0
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