Answer:
11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.
Explanation:
Concentration of sodium stearate acid : c
Moles of sodium stearate =
Volume of the solution = 10.0 mL = 0.010 L
initially c
c 0 0
At equilibrium
(c-x) x x
Dissociation constant of an acid =
Expression of a dissociation constant of an acid is given by:
Solving for x;
x = 0.0041 M
The pOH of the solution:
pH = 14 -pOH
pH = 14 - 2.39 = 11.61
11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.
