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blsea [12.9K]
3 years ago
11

Is a mirror transparent, translucent, or opaque? ​

Chemistry
2 answers:
kozerog [31]3 years ago
6 0
A mirror is opaque, meaning that it reflects the light and images that shine on it's reflective surface.
DochEvi [55]3 years ago
6 0

Answer: It is an opaque object. But the glass is a transparent object because light can pass through it and we can see behind the glass. Thus mirror is opaque but glass is transparent.

Explanation:

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What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, c2h6? in this reaction,
Vitek1552 [10]

Balance equation for combustion of ethane will be:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

To balance the equation:

1. Balance the number of carbon atom on both side:

C₂H₆(g) + O₂(g)--------> CO₂(g) + H₂O(g)

1. balance the number of carbon on both side, as in reactant there are 2 but in product one,

so , multiply the CO₂, by 2 in the product.

2. Balance the number of hydrogen on both side as in reactant the number of hydrogen is 3 but in product it is 6 so, multiplythe number of  H₂O by 3,

so multiply the number of  H₂O by 3 in product.

3. Balance the number of oxygen on both side , as 1 and 2 step increases the number of oxygen and it becomes 7 , so to balance the number of oxygen on both side by mutiplying the  number of  O₂ by 7/2 in reactant .

4. Now, doubling the equation will give balance equation that is:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

8 0
3 years ago
Iron and Oxygen form rust. Compare the mass of iron and oxygen before the reaction with the mass of rust resulting from the reac
LekaFEV [45]
The mass will stay the same because of the conservation of mass
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600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c
Ludmilka [50]

Answer:

k=1.20x10^{-3} s^{-1}

Explanation:

For a first order reaction the rate law is:

v=\frac{-d[A]}{[A]}=k[A]

Integranting both sides of the equation we get:

\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

ln\frac{[A]}{[A]_{0} } =-kt

[A]=[A]_{0}e^{-kt}

ln[A]=ln[A]_{0} -kt

k=\frac{ln[A]_{0}-ln[A]}{t}

therefore k is

k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}

8 0
3 years ago
Match the following metric terms. 1. the basic measure of mass in the metric system meter 2. prefix meaning one-hundredth (.01)
lidiya [134]

Answer: Here's the answer hope this helps

Explanation:

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A student mixed two chemicals to allow them to
Westkost [7]

Answer:

B .it is an exothermic reaction

Explanation:

i need brainleyest

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