Answer:
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = 70.37
Explanation:
Given:
Mass of compound = 0.432 grams
Mass of oxygen = 0.128 grams
Find:
Percentage composition of oxygen
Percentage composition of fluorine
Computation:
Percentage composition of oxygen = [0.128/0.432]100
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = [(0.432 - 0.128)/0.432]100
Percentage composition of fluorine = 70.37
D Continental drift and b
Answer:
0.127M
Explanation:
Molarity of a solution = number of moles (n) ÷ volume (V)
Molar mass of Mg(NO3)2 = 24 + (14 + 16(3)}2
= 24 + {14 + 48}2
= 24 + 124
= 148g/mol
Using the formula, mole = mass/molar mass, to convert mass of Mg(NO3)2 to mole
mole = 14g ÷ 148g/mol
mole = 0.095mol
Volume = 750mL = 750/1000 = 0.75L
Molarity = 0.095mol ÷ 0.75L
Molarity = 0.127M
Answer:
24.5872 meters per second
Rouned 24.6 or 25
