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3 years ago

PLEASEEEE HELP ASAP!!!

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

7 0

Answer:

A. $\text{G and H}$

Step-by-step explanation:

We have been given an image of an ellipse. We are asked to find the vertices of the given ellipse.

The vertices of ellipse are the points that connects the major axis of ellipse.

Upon looking at our given ellipse, we can see that our ellipse has a horizontal major axis, and the points G and H are the points connecting the major axis.

Therefore, the points $\text{G and H}$ are the vertices of our given ellipse and option A is the correct choice.

lidiya [134]3 years ago

6 0

Your answer is point g and h

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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

A student gets 68 marks n therefore gets 85 percent total marks are?

mihalych1998 [28]

Answer:

There are 80 marks in total.

Step-by-step explanation:

Let the number of total marks be $x$ .

The percentage score of the student can be written as the ratio

$\displaystyle \frac{68}{x} = 85\%$ .

However,

$\displaystyle 85\% = \frac{85}{100}$ .

Equating the two:

$\displaystyle \frac{68}{x} = \frac{85}{100}$ .

Cross-multiply (that is: multiple both sides by $100x$ , the product of the two denominators) to get

$85x = 68\times 100$ .

$\displaystyle x = \frac{68\times 100}{85} = 80$ .

In other words, there are 80 marks in total.

4 0

3 years ago

A slug travels 3 centimeters in 3 seconds. A snail travels 6 centimeters in 6 seconds Both travel at constant speeds. Mai says,

Mashutka [201]

Answer:

No I dont agree with Mai. As both the slug and snail are moving with constant speed.

Step-by-step explanation:

Given that:

A slug travels 3 centimeters in 3 seconds.

Speed of slug = distance/ time = 3/3 = 1 cms^-1

A slug travels 3 centimeters in 3 seconds.

Speed of snail = distance/ time = 6/6 = 1 cms^-1

Hence both have constant speeds only the time span for snail is increased which gives more distance it doesn't means that it had covered more distance.

i hope it will help you!

4 0

3 years ago

Can someone help me with 5 and 6

Tom [10]

Number 5 is 42.2

.............

7 0

3 years ago

Can someone help me with this? (screenshot of problem attached)

mote1985 [20]

Answer:

Step-by-step explanation:

Hello. Would love to try and help, your screenshot is not showing up when I click on it though.

7 0

3 years ago