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Setler79 [48]
4 years ago
5

18.95cm equal how many hectometers

Chemistry
1 answer:
Artyom0805 [142]4 years ago
7 0
When converting from centimeters to hectometers you should get 0.001895 hectometers.
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calculate the mass of sodium hydroxide you would need to neutralize a solution containing 7.3g of hydrochloric acid
Mashcka [7]
Molar mass of NaOH = 23 + 16 + 1 = 40.0 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

NaOH + HCl = NaCl + H2O

1*40 g NaOH ------> 1*36.5 g HCl
        g NaOH -------> 7.3 g HCl

36.5 g  = 40 * 7.3

36.5 g = 292

mass ( NaOH ) = 292 / 36.5

mass ( NaOH ) = 8.0 g of NaOH

hope this helps!.

4 0
3 years ago
What is the Law of Conservation of Mass/Matter?
Ostrovityanka [42]

Answer:

O Mass/Matter cannot be created or destroyed

8 0
3 years ago
Which of the following is an example of a double replacement reaction?
Nookie1986 [14]
B) is an example of a Double Displacement Reaction:

<span>Ba  Cl2 + K2 CO3  ---> Ba  CO3 + 2K   Cl 
</span>A    B       C   D             A    D           B   C
6 0
3 years ago
Read 2 more answers
2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2
miv72 [106K]
<h3>Answer:</h3>

4 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN]   2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

[Given]   5.0 g AgNO₃

<u>Step 2: Identify Conversions</u>

[Reaction - Stoich] 2AgNO₃ → 2AgCl

Molar Mass of Ag - 107.87 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.0 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{2 \ mol \ AgCl}{2 \ mol \ AgNO_3})(\frac{143.22 \ g \ AgCl}{1 \ mol \ AgCl})
  2. Multiply/Divide:                                                                                                  \displaystyle 4.21533 \ g \ AgCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

4.21533 g AgCl ≈ 4 g AgCl

3 0
3 years ago
Precipitation that flows into river, lakes, and streams is called
mars1129 [50]

This would be the downward movement of water. It begins flowing and continues in a downward movement moving throughout,

7 0
4 years ago
Read 2 more answers
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