Molar mass of NaOH = 23 + 16 + 1 = 40.0 g/mol
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
NaOH + HCl = NaCl + H2O
1*40 g NaOH ------> 1*36.5 g HCl
g NaOH -------> 7.3 g HCl
36.5 g = 40 * 7.3
36.5 g = 292
mass ( NaOH ) = 292 / 36.5
mass ( NaOH ) = 8.0 g of NaOH
hope this helps!.
Answer:
O Mass/Matter cannot be created or destroyed
B) is an example of a Double Displacement Reaction:
<span>Ba Cl2 + K2 CO3 ---> Ba CO3 + 2K Cl
</span>A B C D A D B C
<h3>
Answer:</h3>
4 g AgCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN] 2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
[Given] 5.0 g AgNO₃
<u>Step 2: Identify Conversions</u>
[Reaction - Stoich] 2AgNO₃ → 2AgCl
Molar Mass of Ag - 107.87 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol
Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig.</em>
4.21533 g AgCl ≈ 4 g AgCl
This would be the downward movement of water. It begins flowing and continues in a downward movement moving throughout,