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romanna [79]
3 years ago
6

Which of the following is an example of a double replacement reaction?

Chemistry
2 answers:
Nookie1986 [14]3 years ago
6 0
B) is an example of a Double Displacement Reaction:

<span>Ba  Cl2 + K2 CO3  ---> Ba  CO3 + 2K   Cl 
</span>A    B       C   D             A    D           B   C
Vinil7 [7]3 years ago
6 0

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Double displacement reactions are defined as the reactions in which exchange of ions takes place.

AB+CD\rightarrow CB+AD

For the given options:

<u>Option a:</u> 3Fe+2O_2\rightarrow Fe_3O_4

This is an example of synthesis reaction.

<u>Option b:</u> BaCl_2+K_2CO_3\rightarrow BaCO_3+2KCl

This is an example of double displacement reaction.

<u>Option c:</u> NiCO_3\rightarrow NiO+CO_2

This is an example of decomposition reaction.

<u>Option d:</u> Cl_2+2NaBr\rightarrow 2NaCl+Br_2

This is an example of single displacement reaction.

From the above information, the correct answer is Option b.

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natural rubidium has the average mass of 85.4678 and is composed of isotopes 85 Rb(mass = 84.9117) and 87 Rb. The ratio of atoms
mote1985 [20]

Answer:

Mass of Rb-87 is 86.913 amu.

Explanation:

Given data:

Average mass of rubidium = 85.4678 amu

Mass of Rb-85 = 84.9117

Ratio of 85Rb/87Rb in natural rubidium = 2.591

Mass of Rb = ?

Solution:

The ration of both isotope is 2.591 to 1. Which means that for 2.591 atoms of Rb-85 there is one Rb-87.

For 100% naturally occurring Rb = 2.591 + 1 = 3.591

% abundance of Rb-85 = 2.591/ 3.591 = 0.722

% abundance of Rb-87 = 1 - 0.722= 0.278

84.9117 × 0.722 + X × 0.278 = 85.4678

61.306 + X × 0.278 = 85.4678

X × 0.278 = 85.4678 - 61.306

X × 0.278 = 24.1618

X =  24.1618 / 0.278

X = 86.913 amu

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Answer:

Explanation:

soluble and insoluble salts are prepared by processes like neutralization reactions, simple displacement reactions and double displacement reactions.

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