Melt chocolate and measure the temperature and then melt wax and measure the temperature and compare his results.
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Answer:
V₂ =31.8 mL
Explanation:
Given data:
Initial volume of gas = 45 mL
Initial temperature = 135°C (135+273 =408 K)
Final temperature = 15°C (15+273 =288 K)
Final volume of gas = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 45 mL × 288 K / 408 k
V₂ = 12960 mL.K / 408 K
V₂ =31.8 mL
Answer: 1. b
2. c
3. a
Explanation: A chemical reaction in equilibrium is actually in a dynamic euqilibrium, which means that changing a condition will make the equilibrium move to counteract the action and reestate the equilibrium.
For example, in the reaction:
N2(g) + 3H2(g) ⇄ 2NH3(g)
1. <u>Adding H2</u>: if you add the reagent, to reestate the equilibrium, the reaction will produce more products so, it will <u>move to the right</u>;
2. A <u>catalyst</u> doesn't interfere in the equilibrium, because it moves to the right and to the left at the same extent. Therefore, there is <u>no effect</u>.
3. <u>Decrease the pressure</u>: when you decrease the pressure of a reaction, the equilibrium will make the pressure increase again by moving towards the side of the reaction which has more molecules, so, it <u>shifts to the left</u>;
Explanation:
Formula for compressibility factor is as follows.
z =
where, z = compressibility factor for helium = 1.0005
P = pressure
= molar volume
R = gas constant = 8.31 J/mol.K
T = temperature
So, calculate the molar volume as follows.
=
= 0.0056
As molar mass of helium is 4 g/mol. Hence, calculate specific volume of helium as follows.
=
= 0.00139
= 0.00139
= 1.39
Thus, we can conclude that the specific volume of Helium in given conditions is 1.39 .