Answer:
Incomplete Question
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Step-by-step explanation:
To answer this question, I'll give conditions which satisfy each of the above characteristics of a scatter plot
1. Negative Correlation:
This type of correlation is achieved when either or both values of X and y on the graph decrease
2. Positive Correlation
This is achieved when the slope (value) of both x and y increase
3. Strong Correlation
This is often achieved when there's uniformity in slope x and y.
4. Weak Correlation
This is achieved when there's no uniforms in slope x and y
5. Linear
Linearity refers to whether a data pattern is linear (straight)
6. Nonlinear
Non-Linearity refers to whether a data pattern is curved.
The probability that it will weigh less than 23.1 ounces is = 0.8643
P(x < 23.1)
= P[(x - \mu) / \sigma < (23.1 - 22) / 1]
= P(z < 1.1)
Using the z table,
= 0.8643
Probability is the branch of arithmetic concerning numerical descriptions of ways in all likelihood an occasion is to occur, or how likely it is that a proposition is authentic. The chance of an occasion is a variety of between zero and 1, where, roughly talking, 0 indicates the impossibility of the event, and 1 indicates truth.
The possibility of an event may be calculated through probability formulation by using simply dividing the favorable wide variety of consequences by the overall range of viable consequences.
Opportunity = the number of ways of achieving achievement. the whole quantity of feasible results. for instance, the possibility of flipping a coin and it being heads is ½, because there's 1 way of having a head and the total wide variety of viable results is 2 (a head or tail). We write P(heads) = ½.
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Let n be the total number of puffs. Now we can write:

Adding the fractional value of n, we get:

Simplifying and rearranging gives us:

Therefore we can simplify to get:

and finally

The fraction of the puff that are tuna is found from:
Answer:
6x²y²
Step-by-step explanation:
6: 1 2 3 6
18: 1 2 3 6 9 18
36: 1 2 3 4 6 9 12 18 36
the common factor for 6 18 and 36 are
1 2 3 6
x² = x × x
y³ = y × y × y
x³ = x × x × x
y³ = y × y × y
x³ = x × x × x
y² = y × y
the common factor are for x and y are
x² y²
Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²