Answer:
The interest is $12
Step-by-step explanation:
You just put the percent in a decimal form(6%-0.06)Then you multiply 200 with 0.06. And the answer you get is the interest
Hope that helps :)
<span>sin θ = opposite/hypotenuse
P(18,24) lies in the first quadrant as both are positive.
x=18
y=24
Hypotenuse = sqrt (18^2 + 24^2)
</span><span>Hypotenuse = 30
</span><span>sin θ = 24/30
</span><span>sin θ = 4/5
</span>θ = sin^-1 (4/5)
<span>θ = 53.13 degrees</span>
so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant
![\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx%7D%7B9%7D~~%2C~~%5Cstackrel%7By%7D%7B-3%7D%29%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bhypotenuse%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B9%5E2%2B%28-3%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B81%2B9%7D%5Cimplies%20c%3D%5Csqrt%7B90%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
25 a² + 20 ab + 4 b²
for formula
find u,v such that: u.v = a
and u+v = b then group according to
=
factor out 5a from :
factor out 2b from :
=
factor out :
=
Refine:
hope this helps!.
Answer:
Answer choice a is correct, the answer would be 4.
Step-by-step explanation:
The histogram shows that the bin from 1-3 has a height of 4 shots, and all of the bins to the right include values of ≥4.
The question asks for the number of games that had less than 4 shots, which means that and number of shots greater than or equal to 4 would not be counted. Thus, only the first bin is included in the answer.
