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3 years ago

In which medium would light have the longest wavelength? water air glass diamond

Chemistry

2 answers:

Mnenie [13.5K]3 years ago

8 0

the answer is b air

Andru [333]3 years ago

4 0

I think the correct answer is air!

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How many chromosomes are in a human gamete ?

RideAnS [48]

Answer:

Explanation:

if if you look at the screenshot it has the explanation

5 0

2 years ago

A star's mass determines the —

kvasek [131]

It’s either A or C sorry I can’t help more

6 0

3 years ago

At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant

ZanzabumX [31]

Answer:

0.24

Explanation:

We are given that

Rate constant for A= $k=0.0180/s$

Rate constant for B,k'=0.0750/s

We have to find the value of equilibrium constant for the reaction

$A\rightleftharpoons B$

Equilibrium constant, for k= $\frac{k}{k'}$

Using the formula

$k=\frac{0.0180}{0.0750}=0.24$

Hence, the value of the equilibrium constant for the reaction

$A\rightleftharpoons B$ at this temperature=0.24

4 0

2 years ago

You will need 384,000 gallons of liquid hydrogen for fuel. Convert to Liters.

Bingel [31]

Answer:

1455360 liters

Explanation:

If there are 3.79 liters in 1 gallon

Do 384,000 × 3.79

Which is 1455360

7 0

1 year ago

The concentration of Pb²⁺ in a sample of wastewater is to be determined by using gravimetric analysis. To a 100.0-mL sample of t

svetoff [14.1K]

Answer:

0.005404 M

Explanation:

$Pb^{2+}(aq) + Na_{2}CO_{3}(aq) ---> PbCO_{3}(s) + 2Na^{+}(aq)$

Since you added an excess of sodium carbonate you warrantied that all the $Pb^{+2}$ in the sample reacted with it. So we can say that the insoluble lead (II) carbonate $PbCO_{3}$ contains all the $Pb^{+2}$ ions in the original sample.

The moles of $PbCO_{3}$ are:

$moles-of-PbCO_{3}=\frac{mass-of-PbCO_{3}}{Molecular-weight-of- PbCO_{3}}=\frac{0.1443g}{267\frac{g}{mol}}=0.00054 mol$

One mol of $Pb^{+2}$ is required to form one mol of $PbCO_{3}$ . So, the stoichiometric relationship between them is 1:1.

$Pb^{+2} +CO_{3}^{-2} - - - > PbCO_{3}$

Knowing this, 0.00054 is also the number of moles of $Pb^{+2}$ in the original sample.

So, the concentration of $Pb^{+2}$ in the original sample is:

$M = \frac{mol-of-Pb^{+2}}{volume-wastewater-(liters)}=\frac{0.00054}{0.1L}=0.005404 M$

8 0

3 years ago