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Darya [45]
3 years ago
15

Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t

he substance is a pure substance or a mixture, if you can.
Sample A is a solid yellow cube with a total mass of 50.0g. The cube is put into a beaker filled with 250.mL of water. The cube collapses into a small pile of orange powder at the bottom of the beaker. When this powder is filtered out, dried and weighed, it has a total mass of 29.9g If the experiment is repeated with 500.mL of water, the powder that's left over has a mass of 30.0g
Sample B is 100.mLof a clear liquid. The liquid is heated in a flask until it boils, which starts to happen at 66.2°C. As the liquid boils, the temperature continues to rise, until the last of the liquid boils away at 76.0°C..
Determine whether each is a pure substance, mixture, or can't decide.
Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

Sample A is a mixture

Sample B is a mixture

Explanation:

For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.

For sample B, we are told that boiling started at 66.2°C and continued until 76.0°C. The implication of this is that B must be a mixture since it boils over a range of temperatures. Pure substances have a sharp boiling point.

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The Answer is A CH2O

The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.
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Answer:

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Answers only please 100pts and brainliest. you will be reported for wrong answers.
Ierofanga [76]

Answer:

K= 25.16%

Mn= 34.59%

O= 40.25%

Explanation:

KMnO_4

Find the total mass of the compound. You can do this by multiplying by the molar mass.

K=40*1=40\\Mn=55*1=55\\O=16*4=64

add them:

40+55+64=159g

Now convert each element individually to grams using molar mass

1molK(\frac{40gK}{1molK} )=40gK

1molMn(\frac{55gMn}{1molMn} )=55gMn

4molO(\frac{16gO}{1molO})=64gO

Divide by the mass of the compound and multiply by 100

K=\frac{40g}{159g} *100=25.16

Mn=\frac{55g}{159g}*100=34.59

O=\frac{64g}{159g}*100=40.25

5 0
3 years ago
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What is the molarity of a solution made from 0.250 mol of sodium hydroxide and 500 mL of water?
Arlecino [84]

Answer:

\boxed {\boxed {\sf 0.5 \ M \ NaOH}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity= \frac{moles}{liters}

There are 0.250 moles of sodium hydroxide (NaOH) and 500 milliliters of water. We need to convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

\frac{1 \ L}{1000 \ mL}

500 \ mL*\frac{1 \ L}{1000 \ mL}

500*\frac{1 \ L}{1000 }

\frac{500}{1000} \ L=0.5 \ L

Now we have the values to solve for molarity:

  • moles= 0.250 mol NaOH
  • liters= 0.5 L

Substitute the values into the formula.

molarity= \frac{0.250 \ mol \ NaOH}{0.5 \ L}

Divide.

molarity= 0.5 \ mol \ NaOH/ L

  • 1 mole per liter (mol/liter) is equal to 1 Molar or M.
  • Our answer of 0.5 moles of sodium hydroxide per liter is equal to 0.5 M NaOH

molarity= 0.5 \ M \ NaOH

The molarity of the solution is <u>0.5 M NaOH</u>

8 0
3 years ago
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