Answer:
The activation energy is 7.11 × 10⁴ J/mol.
Explanation:
Let's consider the Arrhenius equation.
![lnk=lnA-\frac{Ea}{R} .\frac{1}{T}](https://tex.z-dn.net/?f=lnk%3DlnA-%5Cfrac%7BEa%7D%7BR%7D%20.%5Cfrac%7B1%7D%7BT%7D)
where,
k is the rate constant
A is a collision factor
Ea is the activation energy
R is the ideal gas constant
T is the absolute temperature
The plot of ln k vs 1/T is a straight line with lnA as intercept and -Ea/R as slope. Then,
![\frac{-Ea}{R} =-8.55 \times 10^{3} K^{-1} \\Ea= 8.55 \times 10^{3} K^{-1} \times 8.314 \frac{J}{K.mol} =7.11 \times 10^{4} J/mol](https://tex.z-dn.net/?f=%5Cfrac%7B-Ea%7D%7BR%7D%20%3D-8.55%20%5Ctimes%2010%5E%7B3%7D%20K%5E%7B-1%7D%20%5C%5CEa%3D%208.55%20%5Ctimes%2010%5E%7B3%7D%20K%5E%7B-1%7D%20%5Ctimes%208.314%20%5Cfrac%7BJ%7D%7BK.mol%7D%20%3D7.11%20%5Ctimes%2010%5E%7B4%7D%20J%2Fmol)
A solute is a substance that dissolves into another substance , and forms a solution.
Answer:
205K
Explanation:
The following were obtained from the question:
n = 4moles
P = 5.6atm
V = 12L
R = 0.082atm.L/Kmol
T =?
PV = nRT
T = PV/nR
T = (5.6 x 12)/ (4 x 0.082)
T = 205K
Answer:You're answer is D: it is converted to kinetic energy
Explanation:
During a change of phase, the average kinetic energy of the molecules stays the same, but the average potential energy changes. ... My interpretation is that during a phase change, the temperature remains equal, but the kinetic energy of its particles increase/decrease.
LINK:
https://chemistry.stackexchange.com/questions/82163/clarification-of-kinetic-energy-during-phase-change