1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Darya [45]
3 years ago
15

Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t

he substance is a pure substance or a mixture, if you can.
Sample A is a solid yellow cube with a total mass of 50.0g. The cube is put into a beaker filled with 250.mL of water. The cube collapses into a small pile of orange powder at the bottom of the beaker. When this powder is filtered out, dried and weighed, it has a total mass of 29.9g If the experiment is repeated with 500.mL of water, the powder that's left over has a mass of 30.0g
Sample B is 100.mLof a clear liquid. The liquid is heated in a flask until it boils, which starts to happen at 66.2°C. As the liquid boils, the temperature continues to rise, until the last of the liquid boils away at 76.0°C..
Determine whether each is a pure substance, mixture, or can't decide.
Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

Sample A is a mixture

Sample B is a mixture

Explanation:

For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.

For sample B, we are told that boiling started at 66.2°C and continued until 76.0°C. The implication of this is that B must be a mixture since it boils over a range of temperatures. Pure substances have a sharp boiling point.

You might be interested in
Elements and compounds are 2 types of what?
GalinKa [24]
I think the answer is atoms.
3 0
3 years ago
Read 2 more answers
Which percentage represents the amount of Earth's water that is found in oceans?
earnstyle [38]
Your correct answer is C. 97%
7 0
3 years ago
If you were helping a friend do stoichiometry problems, what would you tell them about how they might use subscripts and coeffic
Jet001 [13]
Im not sure if this will help but... your subscripts in a balanced equation are used to calculate the molar mass of the compound. And your coefficients are used to get the ratios. so for example we have this balanced equation
Be3N2 + 6H2O= 3Be(OH)2 + 2NH3  and you have to find the molar mass of 6h2o, you need to multiply the subscript by the atomic mass and then add them together to get the overall molar mass.  * 2(1.01) + 16.00= 18.02 g/mol
and if a question wants to know the limiting or excess regent you would use the coefficients to find out the ratio between the compounds.
 
8 0
3 years ago
Read 2 more answers
How many molecules are in 0.26 mol of CO2
Dominik [7]
<span>1 mole of CO2 = 6.023*10^23 molecules.3 moles of CO2 = 3*6.023*10^23 moleculestherefore, 3 moles of CO2 = 18069*10^20 molecules.
</span>
7 0
3 years ago
Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i
Ket [755]

Answer:

            Empirical Formula  =  C₁₀H₂₀O

Solution:

Data Given:

                      Mass of Menthol  =  9.045 × 10⁻² mg  =  9.045 × 10⁻⁵ g

                      Mass of CO₂  =  0.2546 mg  =  0.0002546 g

                      Mass of H₂O  =  0.1043 mg  =  0.0001043 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

                      %C  =  (2.814) × (12 ÷ 44) × 100

                      %C  =  2.814 × 0.2727 × 100

                      %C  =  76.73 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

                      %H  =  (1.153) × (2.02 ÷ 18.02) × 100

                      %H  =  1.153 × 0.1120 × 100

                     %H  =  12.91 %


                      %O  =  100% - (%C + %H)

                      %O  =  100% - (76.73% + 12.91%)

                      %O  =  100% - 89.64%

                     %O  =  10.36 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 76.73 ÷ 12.01

                     Moles of C  =  6.3888 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 12.91 ÷ 1.01

                      Moles of H  =  12.7821 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 10.36 ÷ 16.0

                      Moles of O  =  0.6475 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     O

            6.3888                              12.7821                            0.6475

     6.3888/0.6475                  12.7821/0.6475                 0.6475/0.6475

               9.86                                   19.74                                   1

             ≈ 10                                      ≈ 20                                     1

Result:

         Empirical Formula  =  C₁₀H₂₀O₁

8 0
4 years ago
Other questions:
  • What is the total number of orbital's in the third principal energy level​
    6·1 answer
  • Please explain, I don't understand.
    14·1 answer
  • ..
    13·2 answers
  • Write the complete balanced equation for the reaction that occurs when C6 H6 combusts in O2. (4 points)
    13·2 answers
  • A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 305 mL of solution. How many moles o
    7·1 answer
  • Use numbers to indicate the order of the steps in the titration process.
    6·2 answers
  • B. Bromine melts at -7.2°C. What is<br> bromine's melting point in kelvins?
    5·1 answer
  • Which part(s) of a telephone involves the conversion of sound waves to electrical signals?
    12·1 answer
  • 1
    14·1 answer
  • What is The element in group 4 and period 3.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!