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guajiro [1.7K]
3 years ago
15

This is the last one thank you to anyone who helps ​

Chemistry
2 answers:
Mice21 [21]3 years ago
5 0

Chromium-58   Carbon-16    Nitrogen-15    Sulfer-25  Sodium-20 Selenium-80

protons:24               6                      7                16               11                  34

neutrons:34             10                     8                 7               1                    46

electrons:24             6                      7                 16             11                   34

Explanation:

Snowcat [4.5K]3 years ago
4 0
I do not get what this is
You might be interested in
Describe how lead sulfate can be prepared using silver hydroxide​
Anastaziya [24]

Answer:

i would have to add and divide

Explanation:

adding and dividing will get you the answer

4 0
2 years ago
The maximum level of lead allowed in drinking water is 15 mg/kg. What is this concentration in units of parts per million?
Alecsey [184]
15 ppm
1.5 × 10-2 ppm
1.5 × 104 ppm
3.1 ppm
1.5 × 10-2 ppm
6 0
3 years ago
What is the energy of a photon having a wavelength of 2.60 ✕ 10-8 m?<br> J
zvonat [6]

The energy of a photon : 7.645 x 10⁻³⁴ J

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ , Hz

c = speed of light

= 3.10⁸  m/s

λ = wavelength ,m

wavelength λ of 2.60 ✕ 10⁻⁸ m

The energy :

\tt E=h.\dfrac{c}{\lambda}\\\\E=6.626.10^{-34}\times \dfrac{3\times 10^8}{2.6\times 10^{-8}}\\\\E=7.645\times 10^{-34}~J

3 0
3 years ago
What is the volume of gas at 2.00 atm and 200.0 K if it’s original volume was 300.0 L at 0.250 atm and 400.0 K.
Sveta_85 [38]

Answer:

= 18.75 L

Explanation:

Using the combined gas law;

P1V1/T2=P2V2/T2

Where; P1 is the initial pressure, 0.25 atm

V1 is the initial volume 300.0 L

T1 is the initial temperature, 400 K

P2 is 2 atm and

T2 is 200 K

Therefore;

(0.25 × 300)/400 = 2V2/200

V2 = (75 ×200)/(400×2)

     = 18.75 L

6 0
3 years ago
Part b using the mass of the proton 1.0073 amu and assuming its diameter is 1.0×10−15m, calculate the density of a proton in g/c
navik [9.2K]
Assuming that the proton is in the shape of the sphere, let's calculate first its volume in units of cm³:

Volume of sphere = 4/3*πr³
Volume of sphere = 4/3*π{[(1.0×10⁻¹⁵ m * 100 cm/1m)]/2}³
Volume = 5.236×10⁻⁴⁰ cm³

The density is then equal to:
Density of proton = 1.0073 g/5.236×10⁻⁴⁰ cm³
Density = 1.924×10³⁹ g/cm³
3 0
3 years ago
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