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guajiro [1.7K]
3 years ago
15

This is the last one thank you to anyone who helps ​

Chemistry
2 answers:
Mice21 [21]3 years ago
5 0

Chromium-58   Carbon-16    Nitrogen-15    Sulfer-25  Sodium-20 Selenium-80

protons:24               6                      7                16               11                  34

neutrons:34             10                     8                 7               1                    46

electrons:24             6                      7                 16             11                   34

Explanation:

Snowcat [4.5K]3 years ago
4 0
I do not get what this is
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What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M
kari74 [83]

Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)

First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)

=0.5mol

Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

Volume of solution = 500/1000

= 0.5 dm3

Therefore, the molarity is

0.5/0.5

=1.0M

The answer should be B.

3 0
3 years ago
Which of the following is a renewable resource a. copper b. aluminum c. peanut oil d. natural gas​
aliya0001 [1]

Answer: c. peanut oil

Explanation:

8 0
3 years ago
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Alice and Marge are studying the properties of matter. The girls cut some silver-colored magnesium sheets into 3-inch long strip
frosja888 [35]
<span>B) Magnesium reacts in acids</span>
4 0
3 years ago
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Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have
Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of HCl = Moles of NaOH

Considering :-

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

Given  that:

Molarity_{NaOH}=5\ M

Volume_{NaOH}=?\ L

Volume_{HCl}=1\ L

Molarity_{HCl}=0.05\ M

So,  

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

0.05\times 1=5\times Volume_{NaOH}

Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L

<u>The volume of NaOH required is - 0.01 L</u>

3 0
3 years ago
3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
xenn [34]

Hence, concentration of base is 1.17 M
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