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3 years ago

This is the last one thank you to anyone who helps

Chemistry

2 answers:

Mice21 [21]3 years ago

5 0

Chromium-58 Carbon-16 Nitrogen-15 Sulfer-25 Sodium-20 Selenium-80

protons:24 6 7 16 11 34

neutrons:34 10 8 7 1 46

electrons:24 6 7 16 11 34

Explanation:

Snowcat [4.5K]3 years ago

4 0

I do not get what this is

You might be interested in

1. Calculate the mass (in grams) of 3.8 moles of the following:

muminat

Explanation:

Given;

Number of moles of the elements = 3.8moles

Molar mass of Gold = 196.966g/mol

Molar mass of Magnesium = 24.3g/mol

Molar mass of Tin = 118.710g/mol

Molar mass of Bromine = 79.904g/mol

Mass = number of moles x molar mass

Mass of Gold = 3.8 x 196.966 = 748.5g

Mass of Magnesium = 3.8 x 24.3 = 92.3g

Mass of Tin = 3.8 x 118.710 = 451.1g

Mass of Bromine = 3.8 x 79.904 = 303.6g

4 0

2 years ago

When aluminum (Al) reacts with chlorine gas (Cl2), aluminum chloride (AlCl3) is produced according to the balanced equation belo

andreyandreev [35.5K]

The balanced reaction shows for every 2 Aluminum we need 3 Chloride gas.

20 Al * (3 Cl / 2 Al) = 30 Cl
We have 45 Cl ... Which is more than enough for 20 Al
We have excess Cl
Then the limiting reagent = Al

5 0

2 years ago

Read 2 more answers

HELP ME, MARKED AS BRAINEST

ELEN [110]

Answer:

The answer is B

Explanation:

2Na + 2H2O = 2NaOH + H2

5 0

2 years ago

A civil engineering student is considering buying an electric car. However, the conscious student wants to make sure her carbon

svetlana [45]

Answer:

$\text{An gasoline-powered vehicle has }\\\boxed{\text{five times the carbon footprint}}\text{ of an electric vehicle.}$

Explanation:

1. Miles travelled in an average month

$\text{Miles} = \text{1 mo} \times \dfrac{\text{52 wk}}{\text{12 mo}} \times \dfrac{\text{5 da}}{\text{1 wk}} \times \dfrac{\text{16 mi}}{\text{1 da}} = \text{347 mi}$

2. Using a gasoline powered vehicle

(a) Moles of heptane used

$n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}$

(b) Equation for combustion

C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O

(c) Moles of CO₂ formed

$n = \text{244 mol heptane} \times \dfrac{\text{7 mol CO$_{2}$}}{\text{1 mol heptane}} = \text{1710 mol CO$_{2}$}$

(d) Volume of CO₂ formed

At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.

$V = \text{1710 mol } \times \dfrac{\text{24.0 L}}{\text{1 mol}} \times \dfrac{\text{1 gal}}{\text{3.785 L}} = \textbf{10 800 gal}$

3. Using an electric vehicle

(a) Theoretical energy used

$\text{Theor. Energy} = \text{347 mi} \times \dfrac{\text{1 kWh}}{\text{5.2 mi}} = \text{66.7 kWh theor.}$

(b) Actual energy used

The power station is only 85 % efficient.

$\text{Actual energy used} = \text{66.7 kWh theor.} \times \dfrac{\text{100 kWh actual}}{\text{ 85 kWh theor.}}\times \dfrac{\text{3600 kJ}}{\text{1 kWh}}\\\\ = 2.82\times 10^{5} \text{ kJ}\$

(c) Combustion of CH₄

CH₄ + 2O₂ ⟶ CO₂ +2 H₂O

(d) Equivalent volume of CO₂

The heat of combustion of methane is -802.3 kJ·mol⁻¹

$V= 2.82\times 10^{5}\text{ kJ} \times \dfrac{\text{1 mol methane}}{\text{802.3 kJ}} \times \dfrac{\text{1 mol CO$_{2}$} }{\text{1 mol methane}} \times \dfrac{ \text{24.0 L}}{ \text{1 mol CO$_{2}$}}\\\\ \times \dfrac{\text{1 gal}}{\text{3.875 L}} = \textbf{2180 gal}$

4. Comparison

$\dfrac{V_{\text{gasoline}}}{V_{\text{electric}}} = \dfrac{10800}{2180} = 5.0\\\\ \text{An gasoline-powered vehicle has }\\ \boxed{\textbf{ five times the carbon footprint}}\text{ of an electric vehicle.}$

6 0

3 years ago

Calculate the percent dissociation of trimethylacetic acid in a aqueous solution of the stuff. You may find some useful data in

LuckyWell [14K]

Answer:

percentage dissociation of trimethylacetic acid in a 0.57M aqueous solution = 0.40%

Explanation:

check attachment below for more information o the answer.

3 0

3 years ago

This is the last one thank you to anyone who helps ​

This is the last one thank you to anyone who helps