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IRINA_888 [86]
3 years ago
10

Consider a reliable data transfer protocol that uses only negative acknowledgements. Suppose the sender sends data only infreque

ntly. Would a NAKonly protocol be preferable to a protocol that uses ACKs?
Engineering
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

Refer to explaination

Explanation:

A NAK only protocol is not preferable to a protocol that uses ACKs especially when the sender sends data frequently.

This is because NAK only protocol will be able to detect that a packet has been lost already when the receiver receives the subsequent packet. Also, as the sender only sends data infrequently, NAK only protocol takes a longer time to realize that a packet has been lost.

On the other hand, NAK only protocol is preferred to a protocol that uses ACKs, when the sender sends data out frequently, here the data loss rate is low.

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Respond with TRUE if the symbol of the valve shown below is
nevsk [136]

Answer:

true

Explanation:

bc the right plus left valve

5 0
3 years ago
PWM input and output signals are often converted to analog voltage signals using low-pass filters. Design and simulate the follo
Temka [501]

Answer:

Attached below

Explanation:

PWM signal source has 1 KHz base frequency

Analog filter : with time constant = 0.01 s

low pass transfer function = \frac{1}{0.01s + 1 }

PWM duty cycle is a constant block

Attached below is the design and simulation into Simulink at 25% , 50% and 100% respectively

5 0
3 years ago
The components of your sample mixture are present in trace amounts. Assuming that you will be using GC, what kind of sample intr
Oxana [17]

Answer:

Gas Chromatography (GC or GLC) is a commonly used analytic technique in many ... for quality control as well as identification and quantitation of compounds in a mixture. ... A broad variety of samples can be analyzed as long as the compounds are ... Most analytical gas chromatographs use capillary columns, where the ...

Explanation:

5 0
3 years ago
Various factors to be considered in deciding the factor of safety?
Eduardwww [97]

Answer with Explanation:

There are various factors that needed to be taken into account while deciding the factor of safety some of which are summarized below as:

1) Importance of the structure: When we design any structure different structures have different importance in our society. Take an example of hospital, in case a natural disaster struck's a place the hospital should be the designed to withstand the disaster as it's role in the crisis management following a disaster is well understood. Thus while designing it we need it to have a higher factor of safety against failure when compared to a local building.

2) Errors involved in estimation of strength of materials: when we design any component of any machine or a structure we need to have an exact idea of the behavior of the material and know the value of the strength of the material. But many materials that we use in structure such as concrete in buildings have a very complex behavior and we cannot estimate the strength of the concrete absolutely, thus we tend to decrease the strength of the concrete more if errors involved in the estimation of strength are more to give much safety to the structure.

3) Variability of the loads that may act on the structure: If the loads that act on the structure are highly variable such as earthquake loads amd dynamic loads then we tend to increase the factor of safety while estimating the loads on the structure while designing it.

4) Economic consideration: If our project has abundant funds then we can choose a higher factor of safety while designing the project.

4 0
3 years ago
Prepare 250 cm3 2M NAOH: molar mass M = 40g/mol. calculate substance mass​
charle [14.2K]

Answer: The mass of the substance is 20 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml  = 250 ml   (1cm^3=1ml)

moles of NaOH = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{40g/mol}

Now put all the given values in the formula of molality, we get

2=\frac{x\times 1000}{40\times 250}

x=20g

Therefore, the mass of the substance is 20 g

6 0
3 years ago
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