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ehidna [41]
4 years ago
14

The standard design conditions for air-conditioning systems established by the Air-Conditioning, Heating and Refrigeration Insti

tute (AHRI) are outside temperature ______8F, inside temperature ______8F, with a humidity of ______%.
Engineering
2 answers:
Art [367]4 years ago
7 0

Answer:

95º, 80ºF, 50%.

Explanation:

Standardizing operating conditions for proper appliance production is essential. For this reason, based on the lines of the Air-Conditioning, Heating and Refrigeration Institute, the standard design conditions for air-conditioning systems are outside temperature 95ºF, inside temperature 80ºF, with a humidity of 50%.

kicyunya [14]4 years ago
6 0

Answer:

AHRI Standards for air conditioning:

Outside temperature: 95°F

Inside temperature : 80°F

Humidity: 50%

Explanation:

The Air-Conditioning, Heating and Refrigeration Institute (AHRI) is a trade association that represents the installers and manufacturers of equipment that are used for heating, ventilation and air-conditioning (HVAC). They develop standards that govern the operation and installation of HVAC units in America and Canada.

From their published standards, the specifications for air conditioning a room are:

Outside temperature: 95°F

Inside temperature : 80°F

Humidity: 50%

<em>This can be found published in their frequently updated handbooks.</em>

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Consider a point in a structural member that is subjected to plane stress. Normal and shear stress magnitudes acting on horizont
never [62]

Answer:

C = 132.5 MPa

R = 86.20 MPa

Explanation:

Given

σx = 175 MPa

σy = 90 MPa

τxy = 75 MPa

For the given state of stress at a point in a structural member, determine the center C and the radius R of Mohr’s circle.

We apply the following equation for the center C

C = (σx + σy) / 2

C = (175 MPa + 90 MPa) / 2

C = 132.5 MPa

The Radius can be obtained as follows

R = √(((σx - σy) / 2)² + (τxy)²)

R = √(((175 MPa - 90 MPa) / 2)² + (75 MPa)²)

R = 86.20 MPa

3 0
3 years ago
A specimen of a 4340-steel alloy with a plane strain fracture toughness of 54.8 MPa sqrt(m) (50 ksi sqrt(in.)) is exposed to a s
Lunna [17]

Answer:

critical stress \sigma _c = 1382.67 MPa

Explanation:

given data

plane strain fracture toughness = 54.8 MP

length of surface creak = 0.5 mm

we take here

parameter Y = 1.0

solution

we apply critical stress formula that is

critical stress \sigma _c = \frac{K}{Y\sqrt{\pi \times a} }   .............................1

here K is design stress plane strain fracture toughness and a is length of surface creak so put all these value in equation 1

critical stress \sigma _c  =  \frac{54.8 \times 10^6}{1 \sqrt{\pi \times 5 \times 106{-4}}}    

solve it we get

critical stress  = 1382.67 MPa

As exposed stress 1030 MPa is less than critical stress 1382 MPa

so that fracture will not be occur here

7 0
3 years ago
Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the accoun
DIA [1.3K]

Answer:

The interest is $160000

Explanation:

simple interest formula: I = P * r * t

To find the simple interest, we multiply 200000 × 0.08 × 10 to get 160000

Hope this helps!

4 0
3 years ago
Read 2 more answers
At his review last year, Lucas was promised a 20 percent raise if he met his production goals. Raises were included in today’s p
Murrr4er [49]

Answer: Instrumentality;low

Explanation: Instrumentality is the impact a person have or will be able to render to a given activity or his or her job. The Instrumentality of a person has been found to be proportional to the what outcome of the person's efforts. Especially if the person's explanations are meant.

When a person's expectations are not meant it will cause the person's Instrumentality to be low.

4 0
3 years ago
An exit sign must be:Colored in a way that doesn’t attract attentionIlluminated by a reliable light sourceAt least 3 inches tall
Ksenya-84 [330]

Answer:

Red

Explanation:

5 0
3 years ago
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