Answer:
No, I don't think so at least
Explanation:
In chemistry, you do calculations to find the concentration of a solution with another solution of KNOWN concentration. Without concentrations of either solution, were would you get values from? Where would you start? :3
Answer:
To understand the utility in sequence comparison and in the search for proteins that have a common evolutionary origin, you need to be clear about some concepts about how to evolve proteins. The idea that is accepted is that throughout the evolution some species are giving rise to new ones. Behind this is the genetic variation of organisms, that is, the evolution of genomes and their genes, as well as the proteins encoded by them.
Explanation:
Three ways can be distinguished by which genes evolve, and by proteins: mutation, duplication and shuffling of domains. When differences between homologous protein sequences are observed, these differences change to do with the way of life of the organism, an example of this, bacteria that live in hot springs at very high temperatures have proteins with a very high denaturation temperature, and these proteins are usually richer in cysteines. On the other hand, the fact that in positions of the sequences they remain unchanged (preserved positions), means that these have a special importance for the maintenance of the structure or function of the protein and its modification has not been tolerated throughout of evolution
0.032 Ms = 3.2 × 10^4 s
<em>Step 1</em>. Convert the number to scientific notation.
0.032 = 3.2 × 10^(-2)
<em>Step 2</em>. Convert the measurement to base units.
3.2 × 10^(-2) Ms × (10^6 s/1 Ms) = 3.2 × 10^4 s
Answer:
1.D) CH4 + 2O2 → CO2 + 2H2O
2C)2,1,2
3.D)SIO2 + 4HF → SIF4 + 2H2O
4.D)2As + 6NaOH → 2Na3AsO3 + 3H2
5.C)SiCI4 + 2H2O → SiO2 + 4HCI
Explanation:
equal number of atoms of each elements in both the sides of the chemical equation is required to have an equation in balanced state.
Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
