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Anestetic [448]
2 years ago
11

20 PIONTS PLZ HELP

Chemistry
1 answer:
ozzi2 years ago
3 0

Answer:

4.58g

Explanation:

1.) What is the molar mass of CaCI2?

= 110.98 g/mol

2.) Find the mols

conc =  \frac{mol}{volume(l)}

conc × volume= mol

0.125 M x 0.33 L = 0.04125mol ( 330mL was converted to "L" by dividing 330 by 1000)

3.) The mass(g)

g= mol x atomic weight

g= 110.98g/mol × 0.04125

= 4.58 g

# NOTE M = mol/L

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Elements on the periodic table are arranged by increasing ?
Galina-37 [17]
They are arranged by their atomic mass.
5 0
3 years ago
the elements carbon hydrogen and oxygen are all part of the same blank on the periodic table........ i i think GROUP diangol row
Mrrafil [7]
The elements Carbon, Hydrogen, and Oxygen are all part of Non-Metals.

Hope This Helps! :)
6 0
3 years ago
Among the following options, a valid Lewis structure of __________ cannot be drawn without violating the octet rule.
Murrr4er [49]

Answer:

d. IF3

Explanation:

The Octet rule posits that atoms gain, atom lose, or share electrons in order to have a full valence shell of 8 electrons. This statement occurs when atoms also combine to form molecules until they attain or share eight valence electrons either by losing or gaining eletrons.

From the given options, a valid Lewis structure that cannot be drawn without violating the octet rule is IF3

8 0
2 years ago
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
PLEASE HELP NO LINKS OR FILES
podryga [215]

Answer:

Rise surface fall surface rise

Explanation:

Hope this helps!

5 0
3 years ago
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