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3 years ago

What is non-point source pollution and why is this kind of pollution hard to monitor and control?

Physics

1 answer:

avanturin [10]3 years ago

7 0

Answer:

When the source of pollution is widely distributive in nature, it is called as the Non-point source pollution, for example, acid rain.

Explanation:

the source of pollution when is not concentrated over a particular area or any particular defined pinpoint is termed to be as the Non - point source pollution.

this type of pollution is very hard to be monitored or controlled due to its nature of widely distributive nature of the origin. It has several pathways for the effect to undertake and thus the control over the effect is not easily accessible.

For example, during rain, the tree fall off can enter water stream from any source, either be it open lake or ponds or even street fall offs.

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How much voltage (in terms of the power source voltage bV) will the capacitor have when it has started at zero volts potential d

Archy [21]

Answer:

The voltage is $V = 0.993V_b$

Explanation:

From the question we are told that

The time that has passed is $t = \frac{\tau}{2}$

Here $\tau$ is know as the time constant

The voltage of the power source is $V_b$

Generally the voltage equation for charging a capacitor is mathematically represented as

$V = V_b [1 - e^{- \frac{t}{\tau} }]$

=> $V = V_b [1 - e^{- \frac{\frac{\tau}{2}}{\tau} }]$

=> $V = V_b [1 - e^{- \frac{\tau}{2\tau} }]$

=> $V = V_b [1 - e^{- \frac{1}{2} }]$

=> $V = 0.993V_b$

5 0

3 years ago

The ballistic pendulum is a device used to measure the speed of a projectile such as a bullet. The projectile of mass m is fired

My name is Ann [436]

Answer:

Relation between initial speed of bullet and height h is given as

$v = \frac{m + M}{m}\sqrt{2gh}$

Explanation:

As we know that system of block and bullet swings up to height h after collision

So we have

$(m + M)gh = \frac{1}{2}(m + M)v_1^2$

so we have

$v_1 = \sqrt{2gh}$

so speed of the block + bullet just after the impact is given by above equation

Now we also know that there is no force on the system of bullet + block in the direction of motion

So we can use momentum conservation

$mv = (m + M)v_1$

now we have

$v = \frac{m + M}{m}\sqrt{2gh}$

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3 years ago

To halt the decline in biodiversity, we must do which of the following?

emmainna [20.7K]

adopt ecological conservation practices

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3 years ago

A 0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s.

Reptile [31]

Mass of the ball is m = 0.10kg Initial speed of the Ball v = 15m/s a. When the ball is at maximum height the velocity is 0 Momentum of ball = mass x velocity Momentum = 0.10kg x 0 = 0 b. Getting the maximum height, Using the conservation of energy equation KEinitial = mgh 1/2mVin^2 = mgh => h = v^2/2g h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m Applying the conservation of energy equation at halfway V^2 = 2gh V = square root of (2x9.8x5.96) => V = square root of (116.816) So the velocity at the half way V = 10.81 m/s Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s

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3 years ago

two point charges are placed on x-axis a 2×10 coulomb charge at x=10cm and -1×10-6 coulomb at x=40cm calculate potential at poin

ryzh [129]

Answer:

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Explanation:

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3 years ago