What is non-point source pollution and why is this kind of pollution hard to monitor and control?

Physics

1 answer:

avanturin [10]3 years ago

7 0

Answer:

When the source of pollution is widely distributive in nature, it is called as the Non-point source pollution, for example, acid rain.

Explanation:

the source of pollution when is not concentrated over a particular area or any particular defined pinpoint is termed to be as the Non - point source pollution.

this type of pollution is very hard to be monitored or controlled due to its nature of widely distributive nature of the origin. It has several pathways for the effect to undertake and thus the control over the effect is not easily accessible.

For example, during rain, the tree fall off can enter water stream from any source, either be it open lake or ponds or even street fall offs.

You might be interested in

How do solar panels create electricity

xenn [34]

Answer:

They create electricity from the sun's rays

Explanation:

By the use of "solar cells" or "solar panel", you can trap solar energy in silicon/germanium rods, then you can convert in into electricity too. Solar powered panels convert the sun's rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business.

5 0

3 years ago

If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is

navik [9.2K]

Answer:

15 and Increasing

Explanation:

Hope this helps

Have a wonderful day and many more to come

Alexis~

~A.K.A Moon~

7 0

2 years ago

The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an

yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

$\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}$