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larisa [96]
2 years ago
6

Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 510 m3/s at a location 90 m above the lake s

urface. Determine the total mechanical energy of the river water per unit mass and the power generation potential of the entire river at that location.
Physics
1 answer:
tangare [24]2 years ago
4 0

The mechanical energy of the river water per unit mass is 887.4 J/kg

The power generated is 452.574 MW.

Given:

Average velocity (v) = 3 m/s

Rate = 510 m³/s

Height (h)  = 90 m

We know, that mechanical energy is the sum of potential energy and kinetic energy.

So,

E = \frac{1}{2}×m×v² + m×g×h                    

and energy per mass unit is

E/m =  \frac{1}{2}×v² + g×h

E/m =  \frac{1}{2}×3² + 9.81×90

E/m = 887.4 J/kg

So, mechanical energy per unit mass is 887.4 J/kg.

Power generated is expressed as;

Power generated = energy per unit mass ×rate×density

Density of water = 1000 kg/m³

Power generated = 887.4× 510× 1000

Power generated = 452574000 W

So, the power generated is 452.574 MW.

Learn more about mechanical energy here:

brainly.com/question/15191390

#SPJ4

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Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
slamgirl [31]

Answer:

A.) acceleration= 55.6m/s^2

B.) acceleration of table= 5.0m/s^2

C.) More acceleration

Explanation:

A.) 100N/1.8kg= -55.6

B.) 100N÷20kg= 5

C.) Because since the table would have less mass, it would have had to accelerate more

7 0
3 years ago
A friend claims that throwing a baseball up towards the school roof illustrates gravitational potential energy transforming into
Cloud [144]

Answer:

The Statement is wrong because the reverse is the case as it is the  kinetic energy that is being transformed to gravitational potential energy.

Explanation:

As your friend throws  the baseball into the air the ball gains an initial velocity (u) and this makes the Kinetic energy to be equal to

                    KE = \frac{1}{2} mu^2

Here  m is the mass of the baseball

       Now as this ball moves further upward the that velocity it gained reduce due to the gravitational force and this in turn reduces the kinetic energy of the ball and this kinetic energy lost is being converted to gravitational potential energy which is mathematically represented as (m×g×h)

as energy can not be destroyed but converted to a different form according to the first law of thermodynamics

Looking a the formula for gravitational potential energy we see that the higher the ball goes the grater the gravitational potential energy.

4 0
3 years ago
A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
Snowcat [4.5K]

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

5 0
3 years ago
Read 2 more answers
(a) what will an object weigh on the moon's surface if it weighs 100 n on earth's surface
juin [17]
We know the equation

weight = mass × gravity

To work out the weight on the moon, we will need its mass, and the gravitational field strength of the moon.
Remember that your weight can change, but mass stays constant.

So using the information given about the earth weight, we can find the mass by substituting 100N for weight, and we know the gravity on earth is 10Nm*2 (Use the gravitational field strength provided by your school, I am assuming yours in 10Nm*2)

Therefore,

100N = mass × 10
mass= 100N/10
mass= 10 kg

Now, all we need are the moon's gravitational field strength and to apply this to the equation

weight = 10kg × (gravity on moon)
4 0
3 years ago
If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a fun
inessss [21]

Answer:

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

s=-8t^2+32t...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

\dfrac{ds}{dt}=0

\dfrac{d(-8t^2+32t)}{dt}=0

-16 t + 32 = 0

t = 2 seconds

Put the value of t in equation (1) as :

s=-8(2)^2+32(2)

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

6 0
3 years ago
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