1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa [96]
2 years ago
6

Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 510 m3/s at a location 90 m above the lake s

urface. Determine the total mechanical energy of the river water per unit mass and the power generation potential of the entire river at that location.
Physics
1 answer:
tangare [24]2 years ago
4 0

The mechanical energy of the river water per unit mass is 887.4 J/kg

The power generated is 452.574 MW.

Given:

Average velocity (v) = 3 m/s

Rate = 510 m³/s

Height (h)  = 90 m

We know, that mechanical energy is the sum of potential energy and kinetic energy.

So,

E = \frac{1}{2}×m×v² + m×g×h                    

and energy per mass unit is

E/m =  \frac{1}{2}×v² + g×h

E/m =  \frac{1}{2}×3² + 9.81×90

E/m = 887.4 J/kg

So, mechanical energy per unit mass is 887.4 J/kg.

Power generated is expressed as;

Power generated = energy per unit mass ×rate×density

Density of water = 1000 kg/m³

Power generated = 887.4× 510× 1000

Power generated = 452574000 W

So, the power generated is 452.574 MW.

Learn more about mechanical energy here:

brainly.com/question/15191390

#SPJ4

You might be interested in
Why is it important that a finger be wet<br> before it is touched to a hot clothes iron?
AleksandrR [38]

Why is it important that your finger be wet if you intend to touch it briefly to a hot clothes iron to test its temperature. If your finger is wet, some of the heat transmitted to your finger will be given to the water which has a high specific heat capacity and also a larger latent heat of vaporization.

#carryonlearning

3 0
2 years ago
Lab: Motion
I am Lyosha [343]

Answer: In this lab we wanted to know how motion can be described. So the hypothesis is if the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration. My prediction is that cars travel faster on higher tracts. So the heighten the track was intentionally manipulated. So it is the independent variable the speed of the car is the dependent variable. The speed at the first quarter checkpoint is 1.09 m/s. The speed at the second quarter checkpoint is 1.95 m/s. The speed at the third quarter checkpoint is 2.373.36 m/s. The speed at the finish line is  2.803.00 m/s. The average speed increases as the height increases.

The cars on the higher track travel farther than the cars on the lower track, in the same time.

This means that the cars on the higher track have a greater average speed than those on the lower track. This is demonstrated by the

slope of the higher track line being greater than the slope of the lower track line.

Explanation: put it in notes then send it to files to compress it to submit it.

5 0
2 years ago
Read 2 more answers
Steam is leaving a 4-L pressure cooker whose operating pressure is 150 kPa. It is observed that the amount of liquid in the cook
jeka57 [31]

Answer: a) Mr = 2.4×10^-4kg/s

V = 34.42m/a

b) E = 173J

Ø = 2693.1J

c) Er = 0.64J/s

Explanation: Please find the attached file for the solution

3 0
3 years ago
If 270 watts of power is used in 42 seconds, how much work was done<br>​
navik [9.2K]

Answer: W = 11340J

Explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

So this is the Formula: Power = Work / Time.

<u>Step 1:</u><em><u> Find the Formula</u></em>

P = W / T

<em><u> </u></em>

<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>

W = PT

<u>Step 3:</u><u> </u><u><em>Given.</em></u>

P = 270 Watts, T = 42 seconds

<u>Step 4:</u><u><em> Substitute these values into equation 2 .</em></u>

W = 270(42)

<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>

W = 11340J

The amount of work done was 11340.

~I hope I helped you! :)~

4 0
3 years ago
An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Dete
dezoksy [38]

Answer:43.34 m

Explanation:

Given

acceleration(a)=2 m/s^2

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

Velocity after 6 s

v=u+at

v=0+2\times 6=12 m/s

After this object will start moving under gravity

height reached in first 6 s

s=ut+\frac{at^2}{2}

s=0+\frac{2\times 6^2}{2}

s=36 m

After fuel run out distance traveled in upward direction is

v^2-u^2=2as_0

here v=0

u=12 m/s

a=9.8 m/s^2

0-12^2=2(-9.8)(s)

s_0=\frac{144}{2\times 9.8}=7.34 m

s+s_0=36+7.34=43.34 m

7 0
3 years ago
Other questions:
  • A 0.145 kg baseball is thrown with a velocity of 40 m/s. What is the baseball's momentum?
    12·1 answer
  • The nonmetals include which of the following groups? Use the periodic table to answer the question. Check all that apply. haloge
    8·1 answer
  • Visible light with a wavelength of 480 nm appears Question 33 options:
    7·1 answer
  • As part of their research on cell reproduction, Ms. Kelly's biology class designed various experiments to determine the best con
    15·1 answer
  • Which quantity measures the maximum distance an object on a spring moves from the equilibrium position during oscillation?
    9·2 answers
  • An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi
    10·1 answer
  • Which material produces static charge when rubbed?
    13·1 answer
  • Indigenous people sometimes cook in watertight baskets by placing hot rocks into water to bring it to a boil. What mass of 500ºC
    7·1 answer
  • 24. A car is travelling along an expressway at 90 km/h. The driver spots a stalled car and some traffic congestion on the road a
    8·1 answer
  • !!Help!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!