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larisa [96]
2 years ago
6

Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 510 m3/s at a location 90 m above the lake s

urface. Determine the total mechanical energy of the river water per unit mass and the power generation potential of the entire river at that location.
Physics
1 answer:
tangare [24]2 years ago
4 0

The mechanical energy of the river water per unit mass is 887.4 J/kg

The power generated is 452.574 MW.

Given:

Average velocity (v) = 3 m/s

Rate = 510 m³/s

Height (h)  = 90 m

We know, that mechanical energy is the sum of potential energy and kinetic energy.

So,

E = \frac{1}{2}×m×v² + m×g×h                    

and energy per mass unit is

E/m =  \frac{1}{2}×v² + g×h

E/m =  \frac{1}{2}×3² + 9.81×90

E/m = 887.4 J/kg

So, mechanical energy per unit mass is 887.4 J/kg.

Power generated is expressed as;

Power generated = energy per unit mass ×rate×density

Density of water = 1000 kg/m³

Power generated = 887.4× 510× 1000

Power generated = 452574000 W

So, the power generated is 452.574 MW.

Learn more about mechanical energy here:

brainly.com/question/15191390

#SPJ4

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Cheddar cheese:  consistent make-up

Drinking water:  H20 plus sanitizers like chlorine but is not separable

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The root quadratic equation of 2x^{2}  - 4x - 9 = 0 is x=\frac{2+\sqrt{22}}{2},\:x=\frac{2-\sqrt{22}}{2}

What is the formula used to calculate the quadratic equation?

To solve the quadratic equation use the formula of x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Find the quadratic equation by using the formula ?

On comparing with 2x^{2}  - 4x - 9 = 0

We get , a=2 , b=-4 , c=-9

D=b^{2} +7\\\\\\=(-4)^{2} +7*2*(-9)\\\\=-16-126\\\\=110

By using the formula,

For a quadratic equation of the formax^2+bx+c=0 the solutions are

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

X==\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\c* \:2\left(-9\right)}}{2\c* \:2}\\\\\sqrt{\left(-4\right)^2-4\cdot \:2\left(-9\right)}\\\\

Apply rule,

-(-a)=a\\\\=\sqrt{\left(-4\right)^2+4\cdot \:2\cdot \:9}\\\\

Apply exponent rule,

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(-4)^{2} =4^{2}

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An electron accelerates through a 12.5 V potential difference, starting from rest, and then collides with a hydrogen atom, excit
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Answer:

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all this energy is used to transfer an electron from the ground state to an excited state

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the ground state has n₀ = 1

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     3           ⇒        2

     3           ⇒        1

     2          ⇒         1

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