Which of the following emissions is associated with burning coal? a. sulfur dioxide b. carbon dioxide c. nitrous oxides d. all o
1 answer:
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Answer:
740 N
Explanation:
We are given that
Radius,r=0.3 m
Torque,
We have to find the magnitude of the static frictional force.
According to question
Torque by engine=Torque by static friction
Hence, the magnitude of static frictional force=740 N
Answer:
t = 0.657 s
Explanation:
given,
initial vertical velocity = 7.5 m/s
initial horizontal velocity = 0 m/s
angle = 49◦
using kinetic equation
final velocity in vertical direction
v sinθ = u_y - gt ........................(1)
final velocity in horizontal direction
v cosθ = u_x + a_x × t
here u_x = 0.0 m/s
v cosθ = a_x×t ......................(2)
Dividing equation (1) / (2)
solving for time t
u_y = initial velocity along x direction
acceleration along a_x = 1.4 m/s²
g = acceleration due to gravity = 9.8 m/s²
θ = 43° , u_y = 7.5 m/s
t = 0.657 s
time taken by the particle is t = 0.657 s