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Darya [45]
3 years ago
10

A toy car is tied to a string and pulled across a table horizontally. Which is the

Physics
2 answers:
Arturiano [62]3 years ago
7 0

Answer:

Correct answer is option D

Explanation:

In this question we have given that toy car is tied to a string and pulled across the table

Therefore there must be three forces which will act on toy car, these are as follows

1. Force due to gravity

2. Normal reaction force

3. Tension in string

Force due to gravity F_{g} will act in downward direction therefore to balance it there must be a normal force which will act in upward direction F_{norm} since the toy car is not accelerating in the y direction.

Since the car is accelerating in horizontal direction therefore tension force will act in the horizontal direction therefore, F_{t} will act to the right.

DerKrebs [107]3 years ago
4 0

Answer:

D

Explanation:

With F_{g} acting as a downward force, there must be a normal force counteracting it, because the toy car is not accelerating in the y direction. This force is the Normal Force or F_{norm}.

The Tension force must be going in the horizontal direction because the toy car is being pulled horizontally, so F_{t} mist be going to the right.

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(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is
Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H  = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = \dfrac{1}{2}mv^2

Using Conservation of energy

KE_i + PE_i + KE_f + PE_f

0 + m g H = \dfrac{1}{2}mv^2 + 0

v = \sqrt{2gH}

v = \sqrt{2\times 9.8 \times 105}

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0
2 years ago
Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m
denis23 [38]

Answer:

4.245s

Explanation:

Given that,

Hypothetical value of speed of light in a vacuum is 18 m/s

Speed of the car, 14 m/s

Time given is 6.76 s, and we're asked to find the observed time, T

The relationship between the two times can be given as

T = t / √[1 - (v²/c²)]

The missing variable were looking for is t, and we can find it if we rearrange the formula and make t the subject

t = T / √[1 - (v²/c²)]

And now, we substitute the values and insert into the equation

t = 6.76 * √[1 - (14²/18²)]

t = 6.76 * √[1 - (196/324)]

t = 6.76 * √(1 - 0.605)

t = 6.76 * √0.395

t = 6.76 * 0.628

t = 4.245 s

Therefore, the time the driver measures for the trip is 4.245s

8 0
3 years ago
What is the electric potential v due to the nucleus of hydrogen at a distance of 5.292×10−11 m ?
viktelen [127]

Answer: 27.21 V

Explanation:

The <u>electric potential</u> V_{E} due to a point charge is expressed as:

V_{E}=k\frac{q}{r}

Where:

k=9(10)^{9}\frac{Nm^{2}}{C^{2}} is the <u>electric constant</u>

q=1.6(10)^{-19}C is the <u>electric charge of the hydrogen nucleus</u>, which is positive

r=5.292(10)^{-11}m is the <u>distance</u>

Rewritting the equation with the known values:

V_{E}=9(10)^{9}\frac{Nm^{2}}{C^{2}}\frac{1.6(10)^{-19}C}{5.292(10)^{-11}m}

Finally:

V_{E}=27.21 V

5 0
3 years ago
This is the last question
koban [17]

Answer:

It's C

Explanation:

3 0
3 years ago
Which diagram is the best model for a solid?<br> Substance A<br> Substance B<br> О Substance C
mina [271]

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

7 0
3 years ago
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