The equation given in the question is
<span>h(t)= -16t^2+144
When the height becomes zero, then
- 16t^2 + 144 = 0
16t^2 = 144
(4t)^2 = (12)^2
4t = 12
t = 3
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the fourth option or option "D". I hope that this is the answer that has actually come to your desired help.</span>
Answer:
It ran at an average of 2 meters per second.
Explanation:
Answer:
yes
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
The final speed of the toy car at the end of the given time period is 3.58 m/s.
The given parameters;
- distance traveled by the car, s = 1.2 m
- time of motion of the car, t = 0.67 s
- initial velocity of the car, u = 0
The acceleration of the car is calculated as;
The final velocity of the toy car is calculated as;
Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.
Learn more here: brainly.com/question/20352766
True it’s true because in the book it said all that stuff
