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34kurt
3 years ago
12

Are we the only person in the universe?

Chemistry
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

no..? how would we be the only person in the universe

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A solution contains one or more of the following ions: Ag+, Ca2+, and Co2+. Lithium bromide is added to the solution and no prec
olchik [2.2K]
<h3>Answer:</h3>

#1. Ca²⁺

# 2. Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

#3. 3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

<h3>Explanation:</h3>

The question above concerns solubility of salts or ions in water.

The solution given contains Ag+, Ca2+, and Co2+ ions.

  • In the first case, when Lithium bromide is added to the solution, there is no white precipitate formed.
  • In the second case, the addition of Lithium sulfate results in the formation of a precipitate because of the Ca²⁺ in the solution combined with the SO₃²⁻ from lithium sulfate to form an insoluble CaSO₄.
  • The net ionic equation for the reaction is;

Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

  • From the solubility rules, all sulfates are soluble except BaSO₄, CaSO₄, and PbSO₄.
  • In the third case, the addition of Lithium phosphate results in the formation of a precipitate because Ag⁺ ions in the solution combine with phosphate ions ( PO₄³⁻) from lithium phosphate to form an insoluble salt, Ag₃PO₄.
  • The net ionic equation for the reaction is;

3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

  • According to solubility rules, all phosphates are insoluble in water except Na₃PO₄, K₃PO₄, and (NH₄)₃PO₄.
6 0
3 years ago
What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
REY [17]

Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

5 0
3 years ago
If hydrochloric acid has a [H+] of 1.2 x 10-2 M, what is the pH?<br> 1.9<br> 0 1<br> 1.2<br> O<br> 8
Vanyuwa [196]

Answer:

<h2>1.9</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

pH =  -  log(1.2 \times  {10}^{ - 2} )  \\  = 1.920818...

We have the final answer as

<h3>1.9</h3>

Hope this helps you

7 0
3 years ago
Read 2 more answers
Which equation has both a liquid and a gas as products? 2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscri
Mandarinka [93]
<h2>Let us predict the gas and liquid products in option </h2>

Explanation:

option  1 :  2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscript 2 (g).

Chemical reaction

It is the reactants react to form products .

Chemical equation

It is the method of representing reaction in terms of moles , specifying states , symbols , molecular formulas etc .

This actually gives the complete info about the reaction .

In the above asked question or any other question we can specify the states by writting :

Solid as "S".

Liquid as "L"

Gas as (g).

8 0
3 years ago
Read 2 more answers
What volume of a 2.5 M NaOH solution is required to make 1 liter of a 0.75 M NaOH
defon
V1M1 = V2M2 

<span>V1 × 2.5 = 1 × 0.75,
so     V1 = 0.75/2.5
              = 0.3 </span>
6 0
3 years ago
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