Answer:
H₂SO₄
Explanation:
We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.
Step 1: Calculate the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percent composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the atomic mass of the element
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Divide all the numbers by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
The empirical formula of the compound is H₂SO₄.
<u>The answer is </u><u>9.94 ml.</u>
<h3>
What is density?</h3>
- Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
- Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.
Given,
The density of ethanol, C2H5OH = 0.789 g/mL
= 7.843 g
Therefore, the answer is 9.94 ml
Learn more about density of ethanol,
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<u>The complete question is -</u>
If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?
C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)
Answer:
Increasing the concentration of a substance will increase the rate of reaction because in a conc substance the particles are more clustered together and this causes more effective collisions thus increasing the rate of reaction and when the substance isn't concentrated the particles aren't really close and this reduces the rate of reaction because alot of collisions can't be made compared to that of the concentrated substance
Answer:
The boiling point is the temperature at which the vapor pressure equals the pressure of gas.
The normal boiling point is the temperature at which the vapor pressure equals one atmosphere
Explanation:
Answer:
E° = -1.66 V
Explanation:
The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.
From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;
E° = -1.66 V
