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2 years ago

25) How many total ions would be present when an ionic compound is formed between a

Chemistry

1 answer:

avanturin [10]2 years ago

7 0

Answer:

4 ions

1 M³⁺ ion and 3 NO₃⁻ ions ( Where M³⁺ stands for the group 13 cation).

Explanation:

Group 13 elements are Boron , Aluminium, Galium, Indium and Thalium. When they form ionic compounds they can lose their three valence electrons to form a tripositive (+3) ion. Nitrate ion is a negative ion with a single negative(-1) charge. When these two form a compound 3 univalent negative nitrate ions must combine with one tripositive group 13 element to form a neutral compound. So the total no of ions is 4.

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With your mind. Boom. Lol I'm sorry I don't know I just need points

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2 years ago

How many atoms are in 187 g of Calcium?

N76 [4]

Atomic mass Calcium ( Ca) = 40.078 u.m.a

40.078 g --------------- 6.02x10²³ atoms
187 g ------------------- ??

187 x ( 6.02x10²³) / 40.078 =

1.125x10²⁶ / 40.078 = 2.808x10²⁴ atoms

hope this helps!

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3 years ago

a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu

Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

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3 years ago

What is bromin what is bromine what is bromine

yulyashka [42]

Answer:

Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly colored gas.

3 0

2 years ago

Read 2 more answers

For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57

Lelu [443]

The % yield if 500 g of sulfur trioxide reacted with excess water to produce 575 g of sulfuric acid is calculated using the below formula

% yield = actual yield/ theoretical yield x100

actual yield =575 grams
to calculate theoretical yield
find the moles of SO3 used =mass/molar mass
= 500g/ 80 g/mol =6.25 moles

SO3+H2O=H2SO4
by use of mole ratio of SO3 : H2SO4 which is 1:1 the moles of H2SO4 is also= 6.25 moles

the theoretical yield of H2SO4 is therefore = moles /molar mass
= 6.25 x98= 612.5 grams

%yield is therefore= 575 g/612 g x100= 93.9 %

5 0

2 years ago