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AnnyKZ [126]
3 years ago
14

if i add water to 100ml of a 0.15 m naoh solution until the final volume is 150 ml,what will the molarity of the diluted solutio

n be?
Chemistry
2 answers:
Katena32 [7]3 years ago
7 0

Answer:

0.1 mol×L

Explanation:

Concentration= MOLES of SOLUTE / Volume of SOLUTION

So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml

So, MOLES of SOLUTE

x 100 x 10-L = ??mol; this was our starting solution.

And final CONCENTRATION=

0.15 . mol. 5 x 100 x 10-3L/

= 0.15 mol · L-1 150 x 10 3

=0.1 mol · L

Kay [80]3 years ago
7 0

Answer:

0.1 moles

Explanation:

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Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

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CALCULATOR
suter [353]

Answer: The possible molecular formula will be CO_2

Explanation:

Mass of C= 27.3 g

Mass of O = 72.7 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{27.3g}{12g/mole}=2.275moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{72.7g}{16g/mole}=4.544moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{2.275}{2.275}=1

For O =\frac{4.544}{2.275}=2

The ratio of C : O = 1: 2

Hence the empirical formula is CO_2

The possible molecular formula will be=n\times CO_2

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