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AnnyKZ [126]
3 years ago
14

if i add water to 100ml of a 0.15 m naoh solution until the final volume is 150 ml,what will the molarity of the diluted solutio

n be?
Chemistry
2 answers:
Katena32 [7]3 years ago
7 0

Answer:

0.1 mol×L

Explanation:

Concentration= MOLES of SOLUTE / Volume of SOLUTION

So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml

So, MOLES of SOLUTE

x 100 x 10-L = ??mol; this was our starting solution.

And final CONCENTRATION=

0.15 . mol. 5 x 100 x 10-3L/

= 0.15 mol · L-1 150 x 10 3

=0.1 mol · L

Kay [80]3 years ago
7 0

Answer:

0.1 moles

Explanation:

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algol [13]
It's a natural element because it appears on earth
4 0
3 years ago
When the reaction h3po4(aq) ca(oh)2(aq)→ occurs what is the formula for the salt formed?
Georgia [21]
2H3PO4 + 3Ca(OH)2 ➡ Ca3(PO4)2 + 6H2O.

Hence salt formed is Ca3(PO4)2.
Hope this helps, have a nice day!
7 0
3 years ago
Read 2 more answers
Which best represents the reaction of calcium and zinc carbonate (ZnCO3) to form calcium carbonate (CaCO3) and zinc?
Basile [38]

Answer:

the second one

Explanation:

Ca+ZnCO3 is the same as calcium + zinc -> is equal to CaCo3+Zn and that is calcium carbonate +zinc which is what the statement states

8 0
2 years ago
Read 2 more answers
A small toy car draws a 0.50-mA current from a 3.0-V NiCd (nickel-cadmium) battery. In 10 min of operation, (a) how much charge
adelina 88 [10]

Answer:

0.3 Coulomb charge flows through the toy car.

0.9 Joules of energy is lost by the battery

Explanation:

Current(I)=\frac{charge(Q)}{Time (T)}

a)

Current drawn from the battery = 0.50 mA = (0.50 × 0.001 A)

milli Ampere = 0.001 Ampere

Duration of time current drawn = T = 10 min = 10 × 60 s = 600 s

1 min = 60 seconds

Charge flows through the toy car be Q

0.50\times 0.001 A=\frac{Q}{600 s}

Q=0.50 \times 0.001 A\times 600 s=0.3 C

0.3 Coulomb charge flows through the toy car.

b)

Heat(H)=Voltage(V)\times Current(I)\times Time(T)

Voltage of the battery = V = 3.0 V

Current drawn from the battery = 0.50 mA = (0.50 × 0.001 A)

Duration of time current drawn = T = 10 min = 10 × 60 s = 600 s

H=V\times I\time T=3.0 V\times 0.50 \times 0.001 A\times 600 s

H = 0.9 Joules

0.9 Joules of energy is lost by the battery

4 0
3 years ago
The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 78 minutes.
Darina [25.2K]

The concentration will be 156 minutes later when the rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 78 minutes is 0.275 ug/mL

Half life: It is known as the time needed to minimize the initial concentration to half. It is denoted by the symbol t1/2

For a first order reaction,

t1/2=0.693/k1

The half-life time for a first order reaction is unaffected by the substrate's starting concentration.

Half life of the given drug is 78 min

Total time is 156 min

Number of half lives corresponding to 156 min is 156/78=2

Therefore, the concentration of drug reduced in 156 min =2^2=4 times

Therefore, the number of half-life is present in the given total time is determined by dividing the total time with half-life of the drug.

The initial concentration is 1.1 ug/mL

Final concentration is 1.1/4=0.275 ug/mL

The concentration of drug after 156 min is 0.275 ug/mL

  • Half life is the period for which the initial concentration of a substance becomes half of initial concentration.

Learn more about half life at:

brainly.com/question/24710827

#SPJ9

7 0
2 years ago
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