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enot [183]
3 years ago
13

Consider the following reaction 2A + 3B -> 2C

Chemistry
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

4

Explanation:

Given  reaction is

2A + 3B -> 2C

From the above reaction for every 2 moles of A, 2 moles of C is formed and therefore for every mole of A reacted, 1 mole of C is formed

Now in this case we have 4 moles of A and excess amount of B

So in this case the limiting reagent is A and the excess reagent is B

As in this case A is the limiting reagent so for 4 moles of A reacted, 4 moles of C is formed

But formation of 4 moles of C is just expected because it is just the maximum amount of C formed as during the reaction there can be losses as well if the reaction is not done properly

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As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
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Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

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so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

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Answer:

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