Answer:
The limiting reactant is the Salicylic acid (C₇H₆O₃)
Explanation:
In order to find the limting reactant or the excess reactant of a chemical reaction we have to compare the moles of each reactant to the stoichiometry of the reaction; we usually make rules of three.
First of all we need to convert the mass of the reactants, to moles:
70 g / 138 g/mol = 0.507 moles of salicylic acid
80g / 102 g/mol = 0.784 moles of acetic anhydride
The reaction is: 2C₇H₆O₃ (aq) + C₄H₆O₃(aq) → 2C₉H₈O₄(aq) + H₂O(l)
Ratio is 2:1.
2 moles of salicylic acid need 1 mol of acetic anhydride to react
Then, 0.507 moles of salicylic will react with (0.507 . 1) / 2 = 0.254 moles of acetic anhydride (It's ok, I have 0.784 moles and I only need 0.254 moles, so acetic anhydride still remains, the C₄H₆O₃ is the excess reactant)
In conclussion, the limiting reactant is the Salicylic acid (C₇H₆O₃)
Let's verify: 1 mol of anhyride needs 2 moles of salicylic acid
Therefore, 0.784 moles of anhydride will react with (0.784 . 2) /1 = 1.57 moles. → We do not have enough C₇H₆O₃, we have 0.507 moles but we need 1.57.
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:
Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)
Let me know if you need anything else. :)
- Dotz
12 moles of water H₂O are produced from the combustion of pentane.
Explanation:
We have the following combustion of pentane (C₅H₁₂):
C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of pentane C₅H₁₂ produces 6 moles of water H₂O
then 2 moles of pentane C₅H₁₂ produces X moles of water H₂O
X = (2 × 6) / 1 = 12 moles of water H₂O
Learn more about:
combustion of organic compounds
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Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams
So you would need 1.2kg or 1200 grams to make a 40% solution
