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The Structure of polypropylene(C3H6)n is linear.
- The chemical formula for polypropylene is (C3H6)n.
- It is a polymer with complex structure and also known as polypropene.
- Polypropylene is similar to polyethylene which belongs to polyolefin groups.
- Generally the polymers are synthesized from the polymerization process.
- What is polymerization?
The process in which atom or small molecules joined together repeatedly to form a polymer with complex structure is called as polymerization.
The repeated unit of atom or small molecule is called monomer
<h3>Structure of polypropylene</h3>Polypropylene is synthesized from the polymerization of propylene which is the monomer unit.
It has a linear structure made of propylene hydrocarbon units.
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Answer:
a. X = 0,909
b. X = 0,965
c X = 0,997
Explanation:
The partition coefficient (k) is defined as:
k = Solute in ether / solute in water
a.
Where X is the fraction of solute extracted
3,34 = X / 3-3X
10,02-10,02X = X
10,02 = 11,02X
<em>X = 0,909</em>
b. First extraction:
3,34 = X / 1-X
3,34 - 3,34X = X
3,34 = 4,34X
<em>X = 0,770</em>
That means solute in water will be: 1-0,770 = 0,23
Second extraction:
The second extraction will extract the same fraction of solute, as now you have 0,230 of solute in water you will extract:
0,230×0,770 = <em>0,177</em>
Third extraction:
In the same way, the third extraction will extract:
(0,230-0,177)×0,770 = <em>0,018</em>
Fraction in water×Fraction extracted
That means total solute extracted is:
0,770 + 0,177 + 0,018 = <em>0,965</em>
c. Extracting with 50mL of ether:
First extraction
3,34 = 2X / 1-X
3,34 - 3,34X = 2X
3,34 = 5,34X
<em>X = 0,625</em>
Second extraction:
(1-0,625)×0,625= <em>0,234</em>
Third Extraction:
(1-0,625-0,234)×0,625= <em>0,088</em>
Fourth extraction:
(1-0,625-0,234-0,088)×0,625= <em>0,033</em>
Fifth extraction:
(1-0,625-0,234-0,088-0,033)×0,625= <em>0,013</em>
Sixth extraction:
(1-0,625-0,234-0,088-0,033-0,013)×0,625= <em>0,004</em>
Total extractions gives:
0,625+0,234+0,088+0,033+0,013+0,004 = <em>0,997</em>
I hope it helps!
Answer:
Activation energy, Ea, for the reaction 261.7 kj/mole
Explanation:
Given
Rate constant at 470 ⁰C (K₁) = 1.10 x 10⁻⁴ s⁻¹ and rate constant at 500⁰C (K₂) = 5.7 x 10⁻⁴ s⁻¹
Temperature (T₁) = 470 + 273 = 743 K and
temperature (T₂) = 500 + 273 = 773 K
Activation energy (Eₐ) = ?
Universal gas constant (R) = 8.314 J. K⁻¹. mole⁻¹
We know log =
⇒ log =
⇒ 0.714 =
⇒ Eₐ = j/mole = 261.7 Kj/mole