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katen-ka-za [31]
3 years ago
13

Will mark Brainliest

Chemistry
2 answers:
yarga [219]3 years ago
7 0

Answer:

A) 6

Explanation:

this is because on the ph scale a number of 7 is used to represent neutral and a number lower than 7 is used to represent the strength of an acid and proves that it is acidic. However a number greater than 7 is used to represent a substance that is an alkali

Tasya [4]3 years ago
4 0
The correct answer is A-6
You might be interested in
Fluorine gas reacts with aqueous iron (II) iodine to produce iron (II) fluoride and iodine liquid What is the balanced chemical
Andru [333]

Answer:

F₂ (g) + FeI₂ (aq) →  FeF₂ (aq) +  I₂ (l)

Explanation:

Our reactants are:

F₂ → Fluorine gas, a dyatomic molecule

FeI₂ → Iron (II) iodine

Our products are:

I₂ → Iodine

FeF₂ → Iron (II) fluoride

Then, the reaction is:

F₂ (g) + FeI₂ (aq) →  FeF₂ (aq) +  I₂ (l)

We see it is completely balanced.

6 0
3 years ago
The analysis of a compound gives the following percent composition by mass:
boyakko [2]

Answer:

C15 H31 O4 S

Explanation:

molecular formula is also the same because the value of "n" is 1

5 0
3 years ago
A _____________ is formed when water empties into a lake or ocean
solong [7]

Answer:

a delta

Explanation:

he place where a river enters a lake, larger river, or the ocean is called its mouth. River mouths are places of much activity. As a river flows, it picks up sediment from the river bed, eroding banks, and debris on the water. ... When large amounts of alluvium are deposited at the mouth of a river, a delta is formed.

6 0
3 years ago
NEED HELP WITH THIS CHEMISTRY QUESTION
denis-greek [22]

Answer:

1341541345134514355143

Explanation:

THIS DUMB B~!TCH  GAVE ME THIS ANSWER

8 0
3 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

5 0
3 years ago
Read 2 more answers
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