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kenny6666 [7]
3 years ago
10

For the reaction represented by the equation 2H2 + O2→ 2H2O, how many grams of water can be produced from 6.0 grams of O2?

Chemistry
1 answer:
leonid [27]3 years ago
5 0

Answer:

a. 6 grams

b. 108 grams

c. 2 grams

d. 54 grams

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The Ksp equation Ksp = [Ag+]2[CO32-] is the solubility product constant for which reaction?
DanielleElmas [232]
The solubility product is calculated using the ions that are formed by the dissolution of a solid. Therefore, the reaction for this solubility product expression is:
Ag₂CO₃ → 2Ag⁺ + CO₃⁻²
8 0
3 years ago
Please help!
adoni [48]

2. 15.65 grams of KCl is formed if 25.0 g of Potassium Chlorate, KClO3, decompose.

3. 2.17 moles of H2 gas produced when 100.0 grams of Na is added to the reaction.

4. 7.5 moles of Hydrogen, H2, are needed to react with 2.5 moles of Nitrogen, N2.

Explanation:

2. The balanced equation for the chemical reaction is:

2KClO3 ⇒ 2KCl + 3O2

Data given:

mass of KClO3 = 25 grams, atomic mass of KClO3 = 122.55 grams/mole

KCl produced =?  atomic mass of KCl = 74.55

number of moles = \frac{mass}{atomic mass of one mole}

                              = \frac{25}{122.55}

  number of moles = 0.20 moles of KCO3

2 moles of KClO3  decomposes to give 2KCl

0.21 moles of KClO3 decomposes to give x moles of KCl

\frac{2}{2} = \frac{x}{0.21}

x = 0.21 moles of KCl

mass of KCl = 0.21 x 74.55

                     = 15.65 grams of KCl is formed.

3. data given:

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

mass of Na added = 100 grams, atomic mass of Na = 22.98 grams/mole

moles of H2 =?

Number of moles of Na = \frac{mass}{atomic mass of one mole}

                            = \frac{100}{22.98}

         number of moles of Na = 4.35 moles

2 moles of Na gives 1 mole of H2

4.35 moles of Na will give x moles

\frac{1}{2} = \frac{x}{4.35}

2x = 4.35

x = 2.17 moles of hydroden gas is produced.

4. Data given:

the balanced chemical equation:

N2 + 3H2 → 2NH3

Number of moles of N2 2.5

from the reaction

1 mole of N2 reacts with 3 moles of H2

The molar ratio of the reactant is 1:3

so, \frac{1}{3}= \frac{2.5}{x}

x = 7.5 moles of H2 will react with 2.5 moles of N2.

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3 years ago
Examples of mechanical and physical weathering in our neighborhoods
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4 years ago
Write the formula for the complex ion formed by the metal ion Cr3+ and six NO2- ions as ligands. Decide whether the complex coul
Dmitrij [34]

Answer:The metal complex formed would have the following formula [Cr(NO₂)₆]³⁻. The complex has a net negative charge and hence it can only be isolated as a salt with a positive cation so the formed complex could be isolated as potassium salt. The formula for salt would be K₃[Cr(NO₂)₆].

Explanation:

The metal ion given to us is Cr³⁺ (Chromium) in +3 oxidation state.

The electronic configuration for the metal ion is  [Ar]3d³ so there are vacant 3d metal orbitals  which are available and hence 6 NO₂⁻ ligands can easily attack the metal center and form a metal complex.

The charge on the overall complex can be calculated using the oxidation states of metal and ligand which is provided.  

The (chromium ) Cr³⁺ metal has +3 charge and 6 NO₂⁻ (nitro) ligands have -6 charge and since  the ligands will be  providing a total of 6 - (negative) charge  and hence only 3- (negative ) charge can be neutralized so a net 3- negative charge would be present on the overall complex which is basically present at the metal center :

charge on the complex=+3-6=-3

Let X be the Oxidation state of Cr in complex =[Cr(NO₂)₆]³⁻

                                                          X-6=-3

                                                           X=-3+6

                                                            X=+3

so our calculated oxidation state of Cr is +3 which matches with the provided in question.

As we can see that the overall metal complex has a net negative charge and hence and only positively charged  cations can form a salt with this metal complex and hence only potassium K⁺ ions can form salt with the metal complex.

since overall charge present on the metal complex is -3 so 3 K⁺ ion would be needed to neutralize it and hence the formula of the metal salt would be K₃[Cr(NO₂)₆].

3 0
3 years ago
Question 6<br>Simplify the following expression<br>-3 + 4(a - 3b + 2) - 514 - a + 3b)​
Nimfa-mama [501]
This expression simplified is 3a-9b-509
3 0
3 years ago
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