Answer:
a heterogeneous mixture is a mixture of two or more liquid substances that are immiscible that is they cannot mix
Answer:
3.55atm
Explanation:
We will apply Boyle's law formula in solving this problem.
P1V1 = P2V2
And with values given in the question
P1=initial pressure of gas = 1.75atm
V1=initial volume of gas =7.5L
P2=final pressure of gas inside new piston in atm
V2=final volume of gas = 3.7L
We need to find the final pressure
From the equation, P1V1 = P2V2,
We make P2 subject
P2 = (P1V1) / V2
P2 = (1.75×7.5)/3.7
P2=3.55atm
Therefore, the new pressure inside the piston is 3.55atm
Answer:
0.001 M OH-
Explanation:
[OH-] = 10^-pOH, so
pOH + pH = 14 and 14 - pH = pOH
14 - 11 = 3
[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-
Answer:
6.178 g.
Explanation:
- KCl is ionized in the solution as:
<em>KCl → K⁺ + Cl⁻.</em>
<em></em>
∴ [KCl] = [K⁺] = [Cl⁻] = 0.193 M.
<em>Molarity is defined as the no. of moles of the solute per 1.0 L of the solution.</em>
<em />
∵ M = [(mass/molar mass)KCl][(1000)/(V of the solution)].
<em>∴ mass of KCl = (M)(molar mass of KCl)(V of the solution)/1000</em> = (0.193 M)(74.55 g/mol)(430.0 mL)/1000 = <em>6.178 g.</em>
<em></em>
Molecular orbital energy is the energy associated with each electron in an atom or molecule.
It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.
C2+: Molecular Orbital Energy Diagram
1s2 2s2 2p2
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 0 e-
π2p* ← 0 e-
π2p ← 0 e-
Bond Order: 0
Stability: Unstable
Magnetism: Diamagnetic (no unpaired electrons)
O2-: Molecular Orbital Energy Diagram
1s2 2s2 2p4
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 2 e-
π2p* ← 0 e-
π2p ← 2 e-
Bond Order: 1
Stability: Stable
Magnetism: Paramagnetic (2 unpaired electrons)
For more questions like Molecular orbital theory click the link below:
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