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evablogger [386]
3 years ago
15

2.00 L of 0.500 M H2SO4 (density = 1.030 g/mL) at 25.000°C is mixed with 200. g of a NaOH solution, also at 25.000°C. After stir

ring, the temperature of the solution is 36.820°C. Calculate q for the reaction. (Assume the specific heat capacity of each solution is 4.184 J/g°C. ) Is the reaction exothermic or endothermic?
Chemistry
1 answer:
AfilCa [17]3 years ago
4 0

Answer:

Q = 111.8 kJ;

The reaction is endothermic.

Explanation:

The heat of the mixture can be calculated by the equation:

Q = m*c*ΔT

Where Q is the heat, m is the mass of the solution, c is the specific heat, and ΔT is the variation in the temperature (fina - initial).

The mass of H₂SO₄ is the volume multiplied by its density:

mH₂SO₄ = 2000 mL * 1.030 g/mL = 2060 g

Then the total mass is:

m = 2060 + 200

m = 2260 g

Q = 2260*4.184*(36.820 - 25.000)

Q = 111,468.03 J

Q = 111.8 kJ

The reaction is endothermic because the solution is absorbing heat (Q > 0), which can be noticed by the increase in the temperature. When the reaction loses heat, it is exothermic and the temperature decreases.

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Relate pH values of 9.1, 1.2, and 5.7 to hydronium and hydroxyl ion concentration.
trapecia [35]

Answer:

9.1 = basic  1.2= very acidic  5.7= acidic

Explanation:

8 0
2 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
3 years ago
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Answer:

<u>2</u><u>1</u><u>.</u><u>0</u><u>9</u><u> </u><u>g</u><u> </u><u>of</u><u> </u><u>AgCl</u>

Explanation:

Hopefully the picture is clear and the method is understandable.

For more information go to

https://socratic.org/questions/5631d10b11ef6b4609a78ee2

7 0
2 years ago
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I’m pretty sure it’s b
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Wich of thses is an example of an environment changing slowly?
EleoNora [17]
I think It's letter A
7 0
3 years ago
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