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3 years ago

Explain the structure of an atom. Make sure to include the charges of the subatomic particles.

1 answer:

Ber [7]3 years ago

5 0

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus of the atom contains the protons and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged)

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Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

3 years ago

the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel

shtirl [24]

<u>Answer:</u> The entropy change of the process is $2.0\times 10^2J/K$

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

$\Delta S=n\times \frac{\Delta H_{f}}{T}$

where,

$\Delta S$ = Entropy change

n = moles of acetone = 6.3 moles

$\Delta H_{f}$ = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol (Conversion factor: 1 kJ = 1000 J)

T = temperature of the system = $-94.7^oC=[273-94.7]=178.3K$

Putting values in above equation, we get:

$\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K$

Hence, the entropy change of the process is $2.0\times 10^2J/K$

4 0

3 years ago

ASAP PLEASEE

Lesechka [4]

Answer:

Joe Mama Formula

Explanation:

JoeMamic Acid is the answer

4 0

2 years ago

If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?

Maru [420]

Answer:

$1.2x10^{24}g$

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

$\frac{2.00g}{1nail}$

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

$6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g$

Best regards!

8 0

2 years ago

Distinguish between an absorption spectrum and an emission spectrum. With which did Bohr work?

Marianna [84]

Answer:

Bohr used emission spectrum for its mono atomic model....

Explanation:

Emission Spectrum is produced when atoms are excited by energy. After excitation, they emit this energy in the form of different wavelengths according to the type of atom and produce a unique fingerprint of themselves called as it's emission spectrum.

Absorption Spectrum is a type of spectrum that is produces when photons of light are absorbed by electrons at one state. they jump to another state and may cause scattering. This produces a specific absorption spectrum for that specific atom.

4 0

2 years ago