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Sholpan [36]
2 years ago
11

1. The half-life of Co-60 is 5.3 years. If the initial mass of the sample is 1000g, how much will remain after 15.9 years.

Chemistry
1 answer:
mixer [17]2 years ago
8 0

Answer:

125 g

Explanation:

The following data were obtained from the question:

Half-life (t½) = 5.3 years.

Original amount (N₀) = 1000 g

Time (t) = 15.9 years.

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 5.3 years.

Time (t) = 15.9 years.

Number of half-lives (n) =?

n = t / t½

n = 15.9 / 5.3

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the amount of Co–60 that is remaining. This can be obtained as follow:

Original amount (N₀) = 1000 g

Number of half-lives (n) = 3

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2³ × 1000

N = 1/8 × 1000

N = 0.125 × 1000

N = 125 g

Therefore, the amount of Co–60 that is remaining is 125 g

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Answer:

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Apparatus arranged to measure the volume of gas in a reaction. Reaction mixture is in a flask and gas travels out through a pipe in the top and down into a trough of water. It then bubbles up through a beehive shelf into an upturned glass jar filled with water. The gas collects at the top of the jar, forcing water out into the trough below.

To make oxygen in the laboratory, hydrogen peroxide is poured into a conical flask containing some manganese(IV) oxide. The gas produced is collected in an upside-down gas jar filled with water. As the oxygen collects in the top of the gas jar, it pushes the water out.

Instead of the gas jar and water bath, a gas syringe could be used to collect the oxygen.

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3 years ago
Which two substances bind using a lock-and-key mechanism?
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HELP 20 POINTS <br>A photon has a wavelength of 366 nm. What is the frequency of this photon?​
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A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo
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The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>
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The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

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  • Find the number of moles of the elements in the compound

The number of moles is given by

n = \frac{m}{M}

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Number of moles of Zinc = \frac{2.156}{65} = 0.033 moles

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Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

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brainly.com/question/1603500

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