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Charra [1.4K]
3 years ago
15

a gas has a volume of 55mL and a pressure of 130 atm. what is the pressure of the gas if the volume changes to 100ml?

Chemistry
2 answers:
Masteriza [31]3 years ago
6 0

Answer:

71.5 atm

Explanation:

Use Boyle's Law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

hichkok12 [17]3 years ago
6 0

Answer:

\large \boxed{\text{71.5 atm}}

Explanation:

The only variables are the pressure and the volume, so we can use Boyle's Law.

Data:

p₁ = 130 atm; V₁ =   55 mL

p₂ = ?;            V₂ = 100 mL

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{130 atm} \times \text{55 mL} & = & p_{2} \times\text{100 mL}\\\text{7150 atm} & = & 100p_{2}\\p_{2} & = & \dfrac{\text{7150 atm}}{100}\\\\& = &\textbf{71.5 atm}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{71.5 atm}}$}

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During heat transfer, thermal energy always moves in the same direction: A. COLDHOT B. HOT COLD C. No movement D. HOTHOT
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A standard hydrogen atom has how many neutrons?<br> A. 0<br> B. 3<br> C. 2<br> D. 1
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4 0
3 years ago
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Five calcite, CaCO3 (MM 100.085 g/mol), samples of equal mass have a total mass of 12.2±0.1 g . What is the average mass and abs
Westkost [7]

Answer:

  • <em>The average mass of calcium in each sample is: </em><u>0.978 g</u>

<em />

  • <em>The absolute uncertainty is: </em><u>0.008 g</u>

Explanation:

The <em>absolute uncertainty </em>of the total samples indicated in the statement is ± 0.1 g.

When you multiply or divide quantities with uncertainties, you calculate the final uncertanty by adding the <em>relative uncertainties</em> together.

The relative uncertainty is the absolute uncertainty divided by the quantity:

  • Relative uncertainty = 0.1g / 12.2 g = 0.008

The average mass of calcium is calculated using proportions, along with the molar masses:

  • Molar mass of calcium: 40.078 g/ mol (from a periodic table)

  • Molar mass of calcite: 100.085 g/mol (given)

Proportion:

  • 40.078 g of calcium / 100.085 g of calcite = x / 12.2 g of calcite

  • x = 12.2 × 40.078 / 100.085 g = 4.89 g calcium

So the total mass of calcium in the five samples is 4.89 g, and the average mass in each sample is:

  • Average mass = total mass of five samples / number of samples

  • Average mass = 4.89 g / 5 = <u>0.978 g of calcium</u>

So, the first answer is that the average mass of calcium in each sample is 0.978 g ( keep 3 signficant figures, such as the quntitiy 12.2 shows, as  you have only used multiplication and division).

The absolute uncertainty of each sample is the relative uncertainty multiplied by the average mass of calcium of the five samples, rounded to one decimal:

  • Absolute uncertainty = 0.978 g × 0.008 ≈ 0.008 g

The answer to the secon question is that the absolute uncertaingy of calcium in each sample is 0.008 g.

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The answer is "right".

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