Answer:
How many atoms are in 6.5 moles of zinc? 6.5 moles. 6.02 x 10. 23 atoms = 3.9 x 10. 24 ... 55.8g. 1 mole. 6. What is the mass of 0.250 moles of aluminum?
Explanation:
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Answer: Option (B) is the correct answer.
Explanation:
Thermal energy is defined as the energy present within the molecules of a substance.
Also, when two objects that have different temperature and they are in contact with each other then heat will always flow from hot object to cold object.
For example, if a metal spoon is placed in a hot cup of coffee then heat will flow from hot coffee to the metal spoon.
Therefore, we can conclude that during heat transfer, thermal energy always moves in the same direction: HOT COLD.
Answer:
D. 1
Explanation:
Hydrogen is the chemical element with the symbol H and atomic number 1. With a standard atomic weight of 1.008, hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe, constituting roughly 75% of all baryonic mass.
Answer:
- <em>The average mass of calcium in each sample is: </em><u>0.978 g</u>
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- <em>The absolute uncertainty is: </em><u>0.008 g</u>
Explanation:
The <em>absolute uncertainty </em>of the total samples indicated in the statement is ± 0.1 g.
When you multiply or divide quantities with uncertainties, you calculate the final uncertanty by adding the <em>relative uncertainties</em> together.
The relative uncertainty is the absolute uncertainty divided by the quantity:
- Relative uncertainty = 0.1g / 12.2 g = 0.008
The average mass of calcium is calculated using proportions, along with the molar masses:
- Molar mass of calcium: 40.078 g/ mol (from a periodic table)
- Molar mass of calcite: 100.085 g/mol (given)
Proportion:
- 40.078 g of calcium / 100.085 g of calcite = x / 12.2 g of calcite
- x = 12.2 × 40.078 / 100.085 g = 4.89 g calcium
So the total mass of calcium in the five samples is 4.89 g, and the average mass in each sample is:
- Average mass = total mass of five samples / number of samples
- Average mass = 4.89 g / 5 = <u>0.978 g of calcium</u>
So, the first answer is that the average mass of calcium in each sample is 0.978 g ( keep 3 signficant figures, such as the quntitiy 12.2 shows, as you have only used multiplication and division).
The absolute uncertainty of each sample is the relative uncertainty multiplied by the average mass of calcium of the five samples, rounded to one decimal:
- Absolute uncertainty = 0.978 g × 0.008 ≈ 0.008 g
The answer to the secon question is that the absolute uncertaingy of calcium in each sample is 0.008 g.