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Answer:
that results in an alcohol and a carboxylic acid.
Explanation:
Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.
For Example, when a base such as sodium hydroxide [NaOH] is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.
In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.
i.e Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol
As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:
The reaction goes to completion in the image below:
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
- On addition of reactant at equilibrium shifts the equilibrium in forward direction.
- On addition of product at equilibrium shifts the equilibrium in backward direction.
- On removal of reactant at equilibrium shifts the equilibrium in backward direction.
- On removal of product at equilibrium shifts the equilibrium in forward direction.
Reactants = A , B
Product = C
1. Increase A
On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.
2. Increase B
On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.
3. Increase C
On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.
4. Decease A
On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.
5. Decease B
On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.
6. Decease C
On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.
7. Double A and Halve B
Equilibrium constant of the reaction = K
On doubling A and halving B, equilibrium constant of the reaction = K'
The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.
8. Double both B and C
Equilibrium constant of the reaction = K
On doubling B and C, equilibrium constant of the reaction = K'
K' = 2 K
The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.