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miskamm [114]
4 years ago
12

I WILL GIVE THE BRAINIEST ANSWER TO THE FIRST PERSON TO ANSWER.TIMED QUIZ!!!ANSWER QUICKLY PLEASE.

Chemistry
2 answers:
Paul [167]4 years ago
4 0

Answer:

radiant to chemical

Explanation:

just took a quiz hope helped

melamori03 [73]4 years ago
3 0

Answer:

Radiant to chemical

Explanation:

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3 years ago
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The oxidizing agent our bodies use to obtain energy from food is oxygen (from the air). If you breathe 17 times a minute (at res
nata0808 [166]

Answer:

<em>The volume of the air breath per day is =12240 L day ^ -1 and he volume of oxygen breathe each day is= 2570.4 L</em>

Explanation:

<em>Complete question: </em><em>The oxidizing agent our bodies use to obtain energy from food is oxygen (from the air). If you breathe 17 times a minute (at rest), taking in and exhaling 0.50 L of air with each breath, what volume of air do you breathe each day? Air is 21% oxygen by volume. what volume of oxygen do you breathe each day?</em>

<em>Solution</em>

<em>Given that,</em>

<em>The volume of the air with each breath = 0.50L</em>

<em>The frequency of breath is = 17 times per minute</em>

<em>the next step is to calculate the volume of the air breath per day</em>

<em>The volume of the breathed air = volume of air breathed/ breath * 17 breaths/min * 60 minutes / per hour * 24 hours/ per day</em>

<em>= 0.50L/ breath * 17 breath /min * 60 minutes / per hour * 24 hours/ per day</em>

<em>= 12240 L day ^ -1</em>

<em>The next step is to calculate the oxygen breathed per day:</em>

<em>The volume of oxygen breathed = volume of air breathed * percent oxygen in air/100</em>

<em>= 12240 L day ^ -1 * 21 /100</em>

<em>= 2570.4 L day ^ -1 </em>

<em>Therefore for each day, the volume of oxygen breathe is 2570.4 L</em>

5 0
4 years ago
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ivolga24 [154]

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4 0
3 years ago
63.15 mL of calcium hydroxide is required to titrate 18.9 mL of a 0.200 M H3PO4 solution. What is the molarity of the basic solu
Kruka [31]

Answer:

0.0898M is the molarity of the basic solution

Explanation:

The reaction of calcium hydroxide, Ca(OH)₂ with H₃PO₄ is:

3 Ca(OH)₂ + 2 H₃PO₄ → 6H₂O + Ca₃(PO₄)₂

To solve this question we must find the moles of H3PO4 that react. With the moles and the rection we can find the moles of Ca(OH)2. Using its volume we can find its molarity:

<em>Moles H3PO4:</em>

0.0189L * (0.200mol / L) = 0.00378 moles H3PO4

<em>Moles Ca(OH)2:</em>

0.00378 moles H3PO4 * (3mol Ca(OH)2 / 2mol H3PO4) = 0.00567 moles Ca(OH)2

<em>Molarity:</em>

0.00567 moles Ca(OH)2 / 0.06315L =

<h3>0.0898M is the molarity of the basic solution</h3>

6 0
3 years ago
The electron configuration for Cu is
belka [17]

Answer:

The answer is [Ar] 3d¹⁰ 4s¹

please let me know if I am wrong

4 0
3 years ago
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