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podryga [215]
4 years ago
8

The image below shows two nitrogen atoms. For these two atoms to form a stable molecule, N2, how many electrons would have to be

part of covalent bonds
Chemistry
1 answer:
maxonik [38]4 years ago
7 0
There are six electrons in the covalent bonds.

Two N atoms would be :N:· + ·:N:
An N₂ molecule would be :N:::N: or :N≡N:
This gives each N atom an octet of eight electrons in its valence shell.

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Einstein's equation applies to which of the following?
stepan [7]
It is clearly (a) is Einstein's equation
8 0
3 years ago
Calculate the molarity of a solution made by adding 45.4 g of nano3 to a flask and dissolving it with water to create a total vo
aleksandr82 [10.1K]
Solutions are made up of two non reacting species called solute and solvent. The amount of solute in solvent is known as concentration of that solute. Concentration is often measured in Molarity. Molarity is the amount of solute dissolved in 1 dm3 of solution. Answer to your question is as follow;

3 0
3 years ago
Read 2 more answers
Consider a solution that is 2.5×10−2 M in Fe2+ and 1.1×10−2 M in Mg2+. (Ksp for FeCO3 is 3.07×10−11 and Ksp for MgCO3 is 6.82×10
Bumek [7]

Answer:

This question is incomplete, here's the complete question:

Consider a solution that is 2.1×10−2 M in Fe2+ and 1.6×10−2 M in Mg2+.

Part A

If potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? ANSWER: Fe 2+

Part B

What minimum concentration of K2CO3 is required to cause the precipitation of the cation that precipitates first? ANSWER: [K2CO3] = 1.5×10−9 M

Part C

What is the remaining concentration of the cation that precipitates first, when the other cation just begins to precipitate? (ANSWER IS NOT .021 or 2.0E-6)

Explanation:

Part A

Fe2+ will precipitate first as solubility product of FeCO3 is lesser than solubility product of MgCO3.

Part B

FeCO3\= Fe2+ + CO32-

Ksp = [Fe2+][CO32-] = 3.07 x 10-11

3.07 x 10-11 = (2.1 x 10-2)[CO32-]

[CO32-] = 1.5 x 10-9 M to precipitate the Fe2+ ions

Part C

MgCO3\= Mg2+ + CO32-

Ksp = [Mg2+][CO32-] = 3.07 x 10-11

6.82 x 10-6 = (1.6 x 10-2)[CO32-]

[CO32-] = 4.3 x 10-4 M to precipitate the Mg2+ ions

Ksp = [Fe2+][CO32-] = 3.07 x 10-11

3.07 x 10-11 = [Fe2+](4.3 x 10-4)

[Fe2+] = 7.1 x 10-8 M when the Mg2+ ions precipitates

5 0
3 years ago
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 115.00 u and 117.00 u, with natural abun
denis23 [38]

(115.00)(0.25)+(117.00)(0.75)=\boxed{116.50 \text{ u}}

3 0
2 years ago
If you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite, how many moles of iron(II) nitrite would you recover?
Serhud [2]

If 125 mL of a 3.5 M solution were evaporated, 0.438 moles of iron (II) nitrite would be recovered.

<h3>What is molarity?</h3>

Molarity is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of moles of solute per liter of solution.

We want to find the moles of iron (II) nitrite (solute) in 125 mL of a 3.5 M solution. We will use the definition of molarity.

M = n / V(L)

n = M × V(L) = 3.5 mol/L × 0.125 L = 0.438 mol

where,

  • M is the molarity.
  • n is the number of moles.
  • V(L) is the volume of the solution in liters.

If 125 mL of a 3.5 M solution were evaporated, 0.438 moles of iron (II) nitrite would be recovered.

Learn more about molarity here: brainly.com/question/9118107

5 0
2 years ago
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