Yes, it is correct...........
The volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
<h3>How to calculate volume?</h3>
The volume of a given mass of gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- R = gas law constant
- T = temperature
- n = number of moles
According to this question, 0.98 moles of oxygen gas at 275 k contains a pressure of 2.0 atm. The volume is calculated as follows:
2 × V = 0.98 × 0.0821 × 275
2V = 22.13
V = 11.06L
Therefore, the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
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Answer:
I promise it is the 2nd one
Explanation:
The following diagram shows a stage of a cell during mitosis. <u>Two identical circles are joined in the middle</u> and they have the nucleolus inside the nucleus in the center of the circles.
Answer:
The concentration of SO₂ will decreases
Explanation:
As you can see in the reaction
2 moles of gas ⇆ 3 moles of gas
Based on Le Châtelier's principle, a change doing in a system will produce that the system reacts in order to counteract the change made.
If the pressure is increased, the system will shift to the left in order to produce less moles of gas and decrease, thus, the pressure.
As the system shift to the left, the concentration of SO₂ will decreases
All you have to do is a simple division "parts over the whole"
12.3 grams H/ 110 grams compound x 100= 11.2%
