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Advocard [28]
3 years ago
8

For a popular Broadway musical, the theater box office sold 356 tickets at $80 apiece, 275 tickets at $60 apiece, and 369 ticket

s at $45 apiece. How much money did the box office take in?
Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0
For 356 ticket, each ticket is $80, so all of those tickets cost 356 × 80 = $28,480.
For 275 ticket, each ticket is $60, so all of those tickets cost 275 × 60 = $16,500.
For 369 ticket, each ticket is $45, so all of those tickets cost 369 × 45 = $16,605.

For all of the tickets the box office took in you have to do:
28,480 + 16,500 + 16,605 = 61,585

<u>The answer is $61,585.</u>
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Bob's Skate Shop had a profit of $3,563 during the month of August. The company models its profit using where x is the number of
CaHeK987 [17]

Answer:

The number of skateboard company sell during the month of August = 55

Step-by-step explanation:

We have given,

Profit function for Bob, P = x²+ 10x - 12

Bob's profit during August month is $3,563

That means, P = $3,563

We can use the profit formula given for Bob's profit:

P = x² + 10x - 12

Plug P =$3,563 in above formula.

i.e 3,563 = x² + 10x - 12

or 0 = x² + 10x -12 - 3,563

or 0 = x² + 10x - 3575

or x = 55, -65

Since number of skate boards can not be negative.

So we consider x= 55

Hence the number of skateboard company sell during the month of August = 55.

6 0
3 years ago
A box of manufactured items contains 12 items. of which four are defective
VikaD [51]
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4 0
3 years ago
Three fewer than the sum of c and d
balandron [24]
C+d-3
Hope this helps if you were looking to put it into an expression!
4 0
3 years ago
Maria would like to leave a tip (t) of at least 15% of her dinner bill (b). Which inequality best could be used to find the amou
mr_godi [17]
First let's define the variables of the problem:
 t: Tip
 b: dinner bill.
 We write the inequality based on the following proposition:
 "Maria would like to leave a tip (t) of at least 15% of her dinner bill (b)"
 We have then that the inequation is:
 t> = 0.15b
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3 0
3 years ago
Construct a 98% confidence interval to determine whether there is any difference between the mean drug concentration in tablets
inna [77]

Answer:

Step-by-step explanation:

So, we are given two sites;

Site one: 91.28 , 92.83, 89.35, 91.90 82.85, 94.83, 89.83, 89.00, 84.62, 86.96, 88.32, 91.17, 83.86, 89.74, 92.24, 92.59, 84.21, 89.36, 90.96, 92.85, 89.39, 89.82, 89.91, 92.16, 88.67.

=> The mean = add up all the numbers/ the total numbers (which is 25). = 89.55.

=> The standard deviation = 3.005

SITE TWO: 89.35 86.51 89.04 91.82 93.02 88.32 88.76 89.26 90.36 87.16 91.74 86.12 92.10 83.33 87.61 88.20 92.78 86.35 93.84 91.20 93.44 86.77 83.77 93.19 81.79.

=> The mean= add up all the numbers/ the total numbers (which is 25). = 89.033.

=> Standard deviation = 3.271.

NB: the assumption here is that the variance for both sites are the same.

STEP ONE: DETERMINE THE DEGREE OF FREEDOM AND THE CRITICAL VALUE.

The degree of freedom =( mean of site 1 ) + (mean of site 2) - 2 = (25 + 25) − 2 = 48.

Since the degree of freedom is 48, Recall that the value for alpha given = 0.02. Then, the critical value = 2.407.

STEP TWO: DETERMINE THE STANDARD DEVIATION AND THE STANDARD ERROR FOR BOTH.

Therefore, the standard deviation = √[( 25 - 1) × 3.005^2 + (25 -1) × 3.271^2) ÷ (25 +25 - 2) ] = 3.14.

Also, the standard error = standard deviation × ( √(1/ mean 1 + 1/mean 2) ..

Standard error = 3.14 × [ ✓( 1/25 + 1/25)] = 0.89.

STEP THREE: DETERMINE THE CONFIDENCE INTERVAL.

confidence interval = (89.548 - 89.033 - 2.41 × 0.89, 89.548 - 89.033 + 2.41 × 0.89) = (- 1.62, 2.65).

STEP FOUR: THE HYPOTHESES.

=> THE TWO TAILED TEST.

Jo:μ1​ = μ2​.

Ja: μ1​ ≠ μ2​.

Thus, the rejected region is {t : ∣ t ∣ > 2.7}

As critical value = 2.7 for the degree of freedom which is 48 and α=0.01.

If we do the t - test for this,.we will have;

(89.548 - 89.003)÷ ( standard deviation × √ ( 1/25 + 1/25). = 0.58.

So,from our t - value, is less or equals to the critical value, therefore, the null hypothesis is not rejected.

Also, from the p-value table which gives p=0.565. The p- value is greater than or equal to the alpha value(0.01). therefore, the null hypothesis is not rejected.

We are not going to reject the null hypothesis because the information gathered is not enough.

3 0
2 years ago
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