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Advocard [28]
3 years ago
8

For a popular Broadway musical, the theater box office sold 356 tickets at $80 apiece, 275 tickets at $60 apiece, and 369 ticket

s at $45 apiece. How much money did the box office take in?
Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0
For 356 ticket, each ticket is $80, so all of those tickets cost 356 × 80 = $28,480.
For 275 ticket, each ticket is $60, so all of those tickets cost 275 × 60 = $16,500.
For 369 ticket, each ticket is $45, so all of those tickets cost 369 × 45 = $16,605.

For all of the tickets the box office took in you have to do:
28,480 + 16,500 + 16,605 = 61,585

<u>The answer is $61,585.</u>
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1 < or equal to - v

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A bed is 2400 a discount of 25% was given on the
Brrunno [24]

Answer:

800

Step-by-step explanation:

Given: The selling price of bed is 2400.

          Discount offered is 25%

Lets assume the cost of bed be "x"

Discount offered on the cost price of bed= \frac{25}{100} \times x= 0.25x

∴ Discount offered on the cost price of bed= 0.25x

We know the selling price of bed after discount provided.

Finding the cost price of the bed.

⇒ x-0.25x= 2400

⇒ 0.75x= 2400

cross multiplying both side.

∴ x= \frac{2400}{0.75} = 3200

∴ Cost price of the bed is 3200.

We know selling price of the bed is 2400.

Now, finding the saving.

Saving on the price of bed= Cost price- selling price

Saving= 3200-2400= 800

Hence, saving on the purchase of the bed is 800.

7 0
3 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
2 years ago
Help me please :&gt;&gt;&gt;&gt;&gt;&gt;&gt;
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Answer:

C. Median

Step-by-step explanation:

If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.

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So first divide 7,500 by 150 and you will get 50.Next,do 17X50 which will give you 850.The answer is 850 Gold beads.Hope that helped.Have a happy new year
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3 years ago
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