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LenKa [72]
2 years ago
8

In a democracy,

Mathematics
1 answer:
ruslelena [56]2 years ago
3 0
C. Is the answer I believe. At least in Canada. That’s why we have the senate here. To listen to the majority while still protecting minority rights
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Need help immediately!!!!!!!
Arisa [49]

Answer:

C)

The rate of change/slope is constant, when you calculate it for this problem, it doesn't change for any amount of marbles listed in the table

5 0
3 years ago
Which of the following number is divisible by both 2 and 3​
DENIUS [597]

Answer:

6, 12, 18,

Step-by-step explanation:

u didn't said the numbers but here is the explanation

6÷2=3

6÷3=2

12÷3=4

12÷2=6

18÷2=9

18÷3=6

4 0
3 years ago
Read 2 more answers
Pls help will give brainliest
Ksju [112]
Definition of parallelogram
definition of bisector
reflexive property of congruence
definition of midpoint
6 0
2 years ago
I can’t find the area
evablogger [386]
Divide it into chunks of area you can find. One way to divide it is
.. a rectangle 2 mi x 5 mi at upper left.
.. a rectangle 8 mi x 6 mi down the middle
.. a rectangle 3 mi x 4 mi at lower right
.. a triangle 5 mi x 6 mi at lower left

Then the sum of areas is
.. (2 mi)*(5 mi) +(8 mi)*(6 mi) +(3 mi)*(4 mi) + (1/2)*(5 mi)*(6 mi)
.. = 10 mi^2 +48 mi^2 +12 mi^2 +15 mi^2
.. = 85 mi^2
4 0
2 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
3 years ago
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