Answer:
The runner's average acceleration is 0.102 m/s²
Explanation:
The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m
We need to find the runner's average acceleration
The given is:
→ Initial velocity 5 m/s
→ Final velocity 5.2 m/s
→ Distance 10 meters
→ Acceleration ?
We need a suitable rule for the given
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, a is the acceleration
and s is the distance
Substitute the values above in the rule
→ (5.2)² = (5)² + 2 a (10)
→ 27.04 = 25 + 20 a
Subtract 25 from both sides
→2.04 = 20 a
Divide both sides by 20
→ a = 0.102 m/s²
<em>The runner's average acceleration is 0.102 m/s²</em>
As we know that centripetal force =mv^2/r
given data is
m = mass
v = speed
r = radius
putting values we get
= 85 x 15^2 / 20
= 956.25 N
option d is correct
Answer:
marblebrainiest plz\c cmarble
Explanation:
The speed of a wave, c, is given by the length of the wave, λ, times the frequency (times per second a cycle passes). Since frequency has units of inverse seconds, the units will then be m/s as we expect.
