The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.
To find the answer, we have to know more about the ideal diode.
<h3>
What is an ideal diode?</h3>
- A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
- A semiconductor diode is the kind of diode that is used the most commonly.
- It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
<h3>How to find the current in ideal diode?</h3>
- Here we have given with the values,

- We have the expression for current in mA of the ideal diode with forward biased voltage drop as,

Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.
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I don't know where you live, but chances are you won't see much at all. Light pollution levels have increased so much due to street lamps and other lights that it's practically impossible to see stars in the night time with the naked eye.
The angles of incidence with respect to the normal will the x-rays reflect from the crystal will be
16.60 degrees. Given: wavelength of X-rays, λ= 0.120 nm
Distance, d=0.21 nm
According to Bragg’s diffraction law: nλ = 2dsinθ
thus, 0.120 = 2*0.21sinθ
or θ =
(0.120/2*0.21)
or θ = 16.60 degrees.
The total weight of the load is (mass) x (gravity) x (height) .
Weight = (520 x 4kg) x (9.8 m/s²)
Weight = (2,080 kg) x (9.8 m/s²)
Weight = 20,384 newtons
Work = (force) x (distance)
Work = (20,834 N) x (15 m)
Work = 305,760 Joules
The north and west components of this displacement are 9.19 km and -7.71 km respectively.
<h3>
North component of the displacement</h3>
The north component of the displacement is calculated as follows;
Dy = D sinθ
Dy = 12 km x sin50
Dy = 9.19 km
<h3>West component of the displacement</h3>
Dx = D x cosθ
Dx = - 12 km x cos(50)
Dx = -7.71 km
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