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AURORKA [14]
3 years ago
10

Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.

Physics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

<em>50%</em>

Explanation:

Given

Initial power = 200W

Final power = 300W

Increment = 300 - 200 = 100W

percentage increase = increment/initial power * 100

percentage increase = 100/200 * 100%

percentage increase = 0.5 * 100

percentage increase = 50%

<em>Hence the percentage increase in speed is 50%</em>

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Explanation:

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An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same directi
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The distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

To find the answer, we have to know about the Lorentz transformation.

<h3>What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens?</h3>

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the distance to the Earth at the moment of the landing craft's launch as measured by the aliens.

  • It is given that; the spaceship is 0.200 ly from the Earth when the landing craft is launched.
  • By Lorentz transformation equation, the value of the distance to the Earth at the moment of the landing craft's launch as measured by the aliens will be,

        L=L_0\sqrt{1-\frac{V^2}{c^2} } =0.2ly\sqrt{1-\frac{(0.6c)^2}{c^2} }=0.2ly\sqrt{1-0.36}=  0.16ly

Thus, we can conclude that, the distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

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What is transpiration
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A student holds an egg outside of an open window and let's go. The window is 40 meters above the ground and the egg is falling u
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The distance traveled by the egg after 2 seconds is 19.6 m.

The given parameters:

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The distance traveled by the egg after 2 seconds is calculated as follows;

h = v_0_y t + \frac{1}{2} gt^2\\\\

where;

  • <em />v_0_y<em> is the initial vertical velocity of the egg = 0</em>
  • <em>g </em><em>is acceleration due to gravity = 9.8 m/s²</em>
  • <em>t </em><em>is the time of motion, = 2 s</em>

h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m

Thus, the distance traveled by the egg after 2 seconds is 19.6 m.

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3 years ago
The angle that the Sun’s rays strike a region of Earth determines the amount of heat transferred.
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