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Assoli18 [71]
3 years ago
9

How was your "therapy" session with Eliza? Describe your experience with the therapy program.

Physics
1 answer:
VladimirAG [237]3 years ago
4 0
I'm gonna need more context...
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Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called:
Gelneren [198K]

Answer:

Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called?

Empiricists Is the Correct Answer!

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Happy Labor day!

4 0
3 years ago
11. A depression in the ground due to a cave collapse or acidic water dissolution of limestone is called a
Ierofanga [76]
It is a sinkhole so yeah..  letter A
4 0
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An inductor is connected across an ac source. suppose the frequency of the source is doubled. what happens to the inductive reac
MaRussiya [10]
<span>If an inductor is connected across an ac source and suppose the frequency of the source is doubled, then t</span>he inductive reactance of the inductor is also doubled. The inductive reactance (XL) is the t<span>he opposition to current flowing through a coil in an AC circuit, the </span>impedance measured in Ohms and can be calculated with the following formula:
XL=2*pi*f*L,
where f is the frequency. So, if the frequency is doubled than also the inductive reactance is doubled.
8 0
3 years ago
13. A proton moves at 7.50×107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path o
diamong [38]

The magnetic force acting on a charged particle moving perpendicular to the field is:

F_{b} = qvB

F_{b} is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.

The centripetal force acting on a particle moving in a circular path is:

F_{c} = mv²/r

F_{c} is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.

If the magnetic force is acting as the centripetal force, set F_{b} equal to F_{c} and solve for B:

qvB = mv²/r

B = mv/(qr)

Given values:

m = 1.67×10⁻²⁷kg (proton mass)

v = 7.50×10⁷m/s

q = 1.60×10⁻¹⁹C (proton charge)

r = 0.800m

Plug these values in and solve for B:

B = (1.67×10⁻²⁷)(7.50×10⁷)/(1.60×10⁻¹⁹×0.800)

B = 0.979T

5 0
3 years ago
A cylindrical rod 120 mm long and having a diameter of 15.0 mm is to be deformed using a tensile load of 35,000 N. It must not e
astraxan [27]

Answer: Magnesium Alloy

Explanation:

Cross sectional area A = (pi/4)d sqr

A = pi / 4 x 0.015 sqr

A = 1.76 x 10^-4 m2

Stressed induced in rod S = P/A = 35000/1.76x 10^-4

S= 198.06 M Pa

Reduction in diameter of the titanium alloy = -v (alpha/E) x d

= - 0.33 (( 198.06 X 10^6) / 70 x 10^9 )x 0.015 = - 1.41 x 10^-2 mm

For steel alloy

= - 0.36 (( 198.06 X 10^6) / 150 x 10^9 )x 0.015 = - 1.02 x 10^-2 mm

For magnesium

= 0.27 (( 198.06 X 10^6) / 205 x 10^9 )x 0.015 = 0.391 x 10^-2 mm

The titanium alloy and the steel alloy does not satisfy the second criteria since the reduction in diameter exceeds the allowable limit of 1.2 x 10^2mm
Considering the yield strength of the material, we find the aluminium alloy is not suitable and hence no need to check for the second criteria. By considering the both the given conditions, we find the magnesium alloy is the suitable material.

3 0
3 years ago
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